SQL 兩個表根據同一標識更改次表信息

表結構如下:
create table tab1(
 id int identity,
 tname varchar(50)
 )

create table tab2
(
idd varchar(10),
iname varchar(50)
)


insert into tab1(tname ) //表1數據                  
select 'a0'
union all select 'b1'
union all select 'b2'
union all select 'b3'
union all select 'b4'
union all select 'b5'
union all select 'b6'
union all select 'b7'


insert into tab2(iname)
 //表2數據              
 select 'a0'
union all select 'b1'
union all select 'b2'
union all select 'b3'
union all select 'b4'
union all select 'b5'
union all select 'b6'
union all select 'b7'


表一與表二有個共同點,就是tname和iname一樣,從而我的需求爲,將表一中的id取到表2中對應iname相同值的,從而更新表2中的值

解決方法兩種:


1:

update tab2 set tab2.idd = tab1.id from tab2 left join tab1 on tab2.iname=tab1.tname

2:

 declare @tab_Name varchar(20)
 declare @tab_Name1 varchar(20)

declare @tab_Name2 varchar(20)
declare @tab_Name3 varchar(20)
declare @tab1 table (sid int identity ,tid varchar(20),tname varchar(20))
declare @tcount int

set @tab_Name1='USE_0088_0006'

insert into @tab1 select 所屬支部, 英文縮寫 from [人力資源-人員-基本情況]



set @tcount =1
 while @tcount<1133
   begin
      select  @tab_Name2=tid,@tab_Name3=tname from @tab1 where sid=@tcount

       update USE_0087 set  USE_0087_0048=@tab_Name2 where USE_0087_0049=@tab_Name3
       set @tcount =@tcount+1
   end
   select * from USE_0087

方法還可以優化