js遞歸調用注意return返回值

[javascript] view plain

轉載：  http://blog.csdn.net/a1017680279/article/details/72953887 copy

調用：
            //獲得公司樹結構中的已選中節點
            var selectedNode = $("#resourceTree").tree('getSelected');
            //console.log(selectedNode);
            var rootNode = getTreeRoot(selectedNode);
            console.log('rootNode====')
            console.log(rootNode);
            if(rootNode !=null && rootNode != 'undefined' &&rootNode.text == '金控'){
                alert('金控');
            }else{
                alert('非金控');
            }
遞歸方法：
        //獲得公司結構的節點node對應的最上層節點
        function getTreeRoot(node){
            console.log('getTreeRoot====node');
            console.log(node);
            var parentNode = $("#resourceTree").tree('getParent',node.target);
            console.log('getTreeRoot()=====');
            console.log(parentNode);
            if (parentNode == null){
                console.log('getTreeRoot()=====null');
                console.log(node);
                return node;
            }else{
                console.log('getTreeRoot====else');
                //這裏需要對遞歸方法進行return
                return getTreeRoot(parentNode);
            }
        }

轉載：http://blog.csdn.net/a1017680279/article/details/72953887