題目1 : String reorder
Description
For this question, your program is required to process an input string containing only ASCII characters between ‘0’ and ‘9’, or between ‘a’ and ‘z’ (including ‘0’, ‘9’, ‘a’, ‘z’).
Your program should reorder and split all input string characters into multiple segments, and output all segments as one concatenated string. The following requirements should also be met,
1. Characters in each segment should be in strictly increasing order. For ordering, ‘9’ is larger than ‘0’, ‘a’ is larger than ‘9’, and ‘z’ is larger than ‘a’ (basically following ASCII character order).
2. Characters in the second segment must be the same as or a subset of the first segment; and every following segment must be the same as or a subset of its previous segment.
Your program should output string “<invalid input string>” when the input contains any invalid characters (i.e., outside the '0'-'9' and 'a'-'z' range).
Input
Input consists of multiple cases, one case per line. Each case is one string consisting of ASCII characters.
Output
For each case, print exactly one line with the reordered string based on the criteria above.
aabbccdd 007799aabbccddeeff113355zz 1234.89898 abcdefabcdefabcdefaaaaaaaaaaaaaabbbbbbbddddddee樣例輸出
abcdabcd 013579abcdefz013579abcdefz <invalid input string> abcdefabcdefabcdefabdeabdeabdabdabdabdabaaaaaaa
用map比較好,這個程序耗時太多,哎。。。
代碼如下:
#include <iostream>
//#include <map>
#include <vector>
#include <list>
#include <algorithm>
#include <string>
using namespace std;
bool checkstr(string a)
{
for (unsigned int i=0;i<a.size();i++)
{
if (a[i]<'0'||a[i]>'z'||('9'<a[i]&&a[i]<'a'))
{
return false;
}
}
return true;
}
int main()
{
string sa;
vector<string> va;
list<char>::iterator it1;
//while(cin>>sa)
while(getline(cin,sa))
{
va.push_back(sa);
}
vector<list<char> > la(va.size());
for (unsigned int i=0;i<va.size();i++)
{
for (unsigned int j=0;j<va[i].size();j++)
{
la[i].push_back(va[i][j]);
}
la[i].sort();
}
for (unsigned int i=0;i<va.size();i++)
{
if (checkstr(va[i]))
{
char temp;
it1=la[i].begin();
while (!la[i].empty())
{
cout<<*it1;
temp=*it1;
it1=la[i].erase(it1);
if (it1==la[i].end()&&!la[i].empty())
{
it1=la[i].begin();
}
while(!la[i].empty()&&*it1==temp)
{
++it1;
if (it1==la[i].end()&&!la[i].empty())
{
it1=la[i].begin();
}
}
}
cout<<endl;
}
else
cout<<"<invalid input string>"<<endl;
}
//system("pause");
return 0;
}