SQL Server 完美SPLIT函數

--SQL Server Split函數
--Author:zc_0101 
--說明：
--支持分割符多字節
--使用方法 
--Select * FROM DBO.F_SQLSERVER_SPLIT('1203401230105045','0')    
--select * from DBO.F_SQLSERVER_SPLIT('abc1234a12348991234','1234') 
--Select * from DBO.F_SQLSERVER_SPLIT('ABC',',')   
 

CREATE FUNCTION F_SQLSERVER_SPLIT(@Long_str varchar(8000),@split_str varchar(100))    
RETURNS  @tmp TABLE(        
    ID          inT     IDENTITY PRIMARY KEY,      
    short_str   varchar(8000)    
)    
AS   
BEGIN   
    DECLARE @long_str_Tmp varchar(8000),@short_str varchar(8000),@split_str_length int   
    SET @split_str_length = LEN(@split_str)    
    IF CHARINDEX(@split_str,@Long_str)=1 
         SET @long_str_Tmp=SUBSTRING(@Long_str,@split_str_length+1,LEN(@Long_str)-@split_str_length)
    ELSE
         SET @long_str_Tmp=@Long_str
    IF CHARINDEX(REVERSE(@split_str),REVERSE(@long_str_Tmp))>1    
        SET @long_str_Tmp=@long_str_Tmp+@split_str    
    ELSE   
        SET @long_str_Tmp=@long_str_Tmp    
    IF CHARINDEX(@split_str,@long_str_Tmp)=0
        Insert INTO @tmp select @long_str_Tmp 
    ELSE
        BEGIN
            WHILE CHARINDEX(@split_str,@long_str_Tmp)>0    
                BEGIN   
                    SET @short_str=SUBSTRING(@long_str_Tmp,1,CHARINDEX(@split_str,@long_str_Tmp)-1)    
                    DECLARE @long_str_Tmp_LEN INT,@split_str_Position_END int   
                    SET @long_str_Tmp_LEN = LEN(@long_str_Tmp)    
                    SET @split_str_Position_END = LEN(@short_str)+@split_str_length    
                    SET @long_str_Tmp=REVERSE(SUBSTRING(REVERSE(@long_str_Tmp),1,@long_str_Tmp_LEN-@split_str_Position_END))
                    IF @short_str<>'' Insert INTO @tmp select @short_str    
                END           
        END
    RETURN     
END 

From: http://www.cnblogs.com/zc_0101/archive/2009/06/30/1513776.html

----------------------------------------------------------------------------------------------------

下面是自己換種思路寫的方法

--另外一種設計思路
ALTER FUNCTION F_SQLSERVER_SPLIT_NEW(@Long_str varchar(8000),@split_str varchar(100))    
RETURNS  @tmp TABLE(        
    ID          inT     IDENTITY PRIMARY KEY,      
    short_str   varchar(8000)    
)    
AS   
BEGIN   
    DECLARE @long_str_Tmp varchar(8000),@short_str varchar(8000),@split_str_length int
    SET @split_str_length = LEN(@split_str)
	--NO SPLIT
	IF CHARINDEX(@split_str,@Long_str) = 0
		BEGIN
			set @short_str = @Long_str
			IF @short_str<>'' Insert INTO @tmp select @short_str 	
        END
    ELSE
		BEGIN
			SET @long_str_Tmp = @Long_str 
			--TEMP STR HAS SPLIT
			WHILE(CHARINDEX(@split_str,@long_str_Tmp)> 0)
			BEGIN
				--SAVE THE FIRST SPLIT STR
				set @short_str = substring(@long_str_Tmp,0,CHARINDEX(@split_str,@long_str_Tmp))
				IF @short_str<>'' INSERT INTO @tmp SELECT @short_str
				--SET TEMP STR TO OTHER PARTS
				SET @long_str_Tmp=SUBSTRING(@long_str_Tmp,@split_str_length+1,LEN(@long_str_Tmp)-@split_str_length)		
				--IF TEMP STR NO SPLIT, SAVE HERE
				IF CHARINDEX(@split_str,@long_str_Tmp)= 0 AND @long_str_Tmp <>''
				BEGIN 
					set @short_str = @long_str_Tmp
					INSERT INTO @tmp SELECT @short_str
				END		
			END
		END
	RETURN 
END

上面自己寫的方法還有BUG：以下語句中會出錯。

SELECT * FROM dbo.FN_SQLSERVER_SPLIT('c3058e26-ff3c-4f0d-92a5-76f34340de3b,7f48477c-860e-4a8d-a14f-7844beb6671c', ',');

SELECT * FROM dbo.fn_split('c3058e26-ff3c-4f0d-92a5-76f34340de3b,7f48477c-860e-4a8d-a14f-7844beb6671c', ',');--此方法請看下面

另外提供一個更完美的。

SET QUOTED_IDENTIFIER ON
SET ANSI_NULLS ON
GO
create function fn_split(@SourceSql varchar(8000),@StrSeprate varchar(10))
returns @temp table(AllItem varchar(100))
--實現split功能 的函數
as 
begin
declare @i int
set @SourceSql=rtrim(ltrim(@SourceSql))
set @i=charindex(@StrSeprate,@SourceSql)
while @i>=1
begin
insert @temp values(left(@SourceSql,@i-1))
set @SourceSql=substring(@SourceSql,@i+1,len(@SourceSql)-@i)
set @i=charindex(@StrSeprate,@SourceSql)
end
if @SourceSql<>'\'
insert @temp values(@SourceSql)
return 
end
GO