hdu 1706 An Easy Task

題目鏈接：hdu 1706

#include<iostream>
using namespace std;
bool isLeap(int y)
{
	bool ret = false;
	if(y%4==0&&y%100!=0||y%400==0) ret = true;
	return ret;
}
int main()
{
	int t,n,y,sum;
	cin>>t;
	while(t--)
	{
		cin>>y>>n;
		for( int i = y;n;i++)
		{
			if(isLeap(i)) n--,sum = i;
		}
		cout<<sum<<endl;
	}
	return 0;
}