Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return
0.
You may assume that the version strings are non-empty and contain only digits and the .
character.
The .
character does not represent a decimal point and is used
to separate number sequences.
For instance, 2.5
is not "two and a half" or "half way to version
three", it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37
把字符串以'.'分割,把分割後字符串轉化成整型,逐位比較即可。
class Solution {
public:
int compareVersion(string version1, string version2) {
int val1;
int val2;
int index1 = 0;
int index2 = 0;
while(index1<version1.length() || index2<version2.length()){
val1 = 0;
while(index1<version1.length()){
if(version1[index1] == '.'){
index1++;
break;
}else{
val1 = val1*10 + (version1[index1] - '0');
index1++;
}
}
val2 = 0;
while(index2<version2.length()){
if(version2[index2] == '.'){
index2++;
break;
}else{
val2 = val2*10 + (version2[index2] - '0');
index2++;
}
}
if(val1 < val2){
return -1;
}
if(val1 > val2){
return 1;
}
}
return 0;
}
};