HDU1698(線段樹LAZY)

/*
	TASK:hdu1698	
*/ 
#include<iostream>
#include<cstdio>
const int maxn=100000+10,maxm=100000+10;
using namespace std;
int a[maxn<<2],ans;
void ts(int h,int s,int t,int L,int R,int ys){
	if(L<=s && t<=R)a[h]=ys;
	else{
		if(a[h]>=0){
			a[h*2]=a[h*2+1]=a[h];
			a[h]=-1;
		}
		if(L<=(s+t)/2)ts(h*2,s,(s+t)/2,L,R,ys);
		if((s+t)/2+1<=R)ts(h*2+1,(s+t)/2+1,t,L,R,ys);
	}
}
void cal(int h,int s,int t){
	if(a[h]>=0)ans+=a[h]*(t-s+1);
	else{
		cal(h*2,s,(s+t)/2);
		cal(h*2+1,(s+t)/2+1,t);
	}
}
int main(){
	int i,j,k,m,n,x,y,z,c;	
	cin>>c;
	for(k=1;k<=c;k++){
		ans=0;
		cin>>n>>m;
		a[1]=1;
		for(i=1;i<=m;i++){
			scanf("%d%d%d",&x,&y,&z);
			ts(1,1,n,x,y,z);
		}
		cal(1,1,n);
		printf("Case %d: The total value of the hook is %d.\n",k,ans);
	}
	return 0;
}