一、題目說明
題目347. Top K Frequent Elements,從數組中找出現頻度最高的k個數。難度是Medium!
二、我的解答
求出現頻度最高的數,首先用hash計算各個數出現的頻度,然後找出前k個。
class Solution{
public:
vector<int> topKFrequent(vector<int>& nums,int k){
ump.clear();
for(int i=0;i<nums.size();i++){
ump[nums[i]]++;
}
vector<int> res;
int minFre=INT_MAX,minFreIndex=-1;
for(auto u: ump){
if(res.size()<k){
res.push_back(u.first);
if(minFre > u.second){
minFre = u.second;
minFreIndex = res.size()-1;
}
}else if(u.second > minFre){
res[minFreIndex] = u.first;
minFre = INT_MAX;
for(int j=res.size()-1;j>=0;j--){
if(minFre > ump[res[j]]){
minFre = ump[res[j]];
minFreIndex = j;
}
}
}
}
return res;
}
private:
unordered_map<int,int> ump;
};
性能如下:
Runtime: 40 ms, faster than 5.85% of C++ online submissions for Top K Frequent Elements.
Memory Usage: 11.4 MB, less than 96.77% of C++ online submissions for Top K Frequent Elements.
三、優化措施
用大根堆進行優化:
class Solution{
public:
vector<int> topKFrequent(vector<int>& nums,int k){
unordered_map<int,int> ump;
priority_queue<pair<int,int>> pq;
for(int i=0;i<nums.size();i++){
ump[nums[i]]++;
}
for(auto u: ump){
pq.push(make_pair(u.second,u.first));
}
vector<int> res;
for(int i=0;i<k;i++){
res.push_back(pq.top().second);
pq.pop();
}
return res;
}
};
性能如下:
Runtime: 16 ms, faster than 96.21% of C++ online submissions for Top K Frequent Elements.
Memory Usage: 11.5 MB, less than 67.74% of C++ online submissions for Top K Frequent Elements.