php計算日期數組中連續的天數

接上一篇文章的簽到那個統計有一個算出連續簽到就要去日誌表獲取一段時間內的數據，

 

例如 如下json數組

[
{"oneday_time":1588435200,"oneday":"2020-05-03","week":"0","weektext":"週日","morning":1588455858,"morninghour":"05:44"},
{"oneday_time":1588521600,"oneday":"2020-05-04","week":"1","weektext":"週一","morning":1588556679,"morninghour":"09:44"},
{"oneday_time":1588608000,"oneday":"2020-05-05","week":"2","weektext":"週二","morning":1588648262,"morninghour":"11:11"},
{"oneday_time":1588694400,"oneday":"2020-05-06","week":"3","weektext":"週三","morning":1588716032,"morninghour":"06:00"},
{"oneday_time":1588780800,"oneday":"2020-05-07","week":"4","weektext":"週四","morning":1588811814,"morninghour":"08:36"},
{"oneday_time":1588867200,"oneday":"2020-05-08","week":"5","weektext":"週五","morning":1588892085,"morninghour":"06:54"}]

怎麼算出連續的天數算法如下

$len = 0;
        $i=0;
        $max=array_reduce($resultdata['morning'],function ($a,$b) use(&$len,&$i,$count,$resultdata){
            if ($i+1 == $count){return $a;}
            else {
                if ((strtotime($b['oneday']) + 86400) == strtotime($resultdata['morning'][$i+1]['oneday'])) {
                    $len++;
                } else {
                    if ($len > $a){$a = $len;}
                    $len = 1;
                }
                if ($len > $a) {$a = $len;}
                $i++;
                return $a;
            }
        },1);

順帶還有連續早起，最早起牀，平均起牀

$morningdata = array_column($resultdata['morning'], 'morning');
$morningcolocknumber = count($morningdata);//本週早起
$countmorning = array_sum(array_values($morningdata));
$avgmoring = date('H:i',bcdiv($countmorning, $morningcolocknumber, 0));//平均起牀
$minmorning=date('H:i', min($morningdata))//最早起牀

下面再來說說上面的方法還有沒有其他方法，有的下面這張，

這裏同時告訴array_reduce怎麼獲取key的，也是通過差不多外層傳一個$i,結合array_keys來使用

$count=count($resultdata['morning']);//可替換上面的$morningcolocknumber
        $len = 0;
        $i=0;
        $max=array_reduce($resultdata['morning'],function ($a,$b) use(&$len,&$i,$count,$resultdata){
            if ($i+1 == $count){return $a;}
            else {
                if ((strtotime($b['oneday']) + 86400) == strtotime($resultdata['morning'][$i+1]['oneday'])) {
                    $len++;
                } else {
                    if ($len > $a){$a = $len;}
                    $len = 1;
                }
                if ($len > $a) {$a = $len;}
                $i++;
                return $a;
            }
        },1);