#coding: UTF-8
import threading
import time
import random
# 麪包店算法實現線程鎖
# 爭奪的資源
incNum = 0
class BakeryLock:
def __init__(self, threadCount):
# 取得的號碼
self.number = [0 for _ in range(threadCount)]
# 是否正在取號
self.entering = [False for _ in range(threadCount)]
def lock(self, threadNum):
# 進入麪包店,準備取號
self.entering[threadNum] = True
# 取號
self.number[threadNum] = max(self.number) + 1
# 取號結束
self.entering[threadNum] = False
# 等待前面的顧客買麪包結束
for i in range(threadCount):
# 等待顧客i取號結束
while self.entering[i] :
pass
# 等待前面的顧客i買麪包結束
# 判斷顧客i是否在自己前面的條件:顧客i取的號碼比自己小,如果取的號碼相同,那麼線程id小的優先
while (self.number[i]!=0) and ((self.number[i], i) < (self.number[threadNum], threadNum)):
pass
def unlock(self, threadNum):
self.number[threadNum] = 0
# 使用資源
def achive_resource(threadNum):
print('Now is no.{} thread achive the resource'.format(threadNum))
global incNum
incNum += 1
def start_request(threadNum, bkLock):
iLoopCount = 0
while iLoopCount<5:
bkLock.lock(threadNum)
achive_resource(threadNum)
bkLock.unlock(threadNum)
iLoopCount+=1
if __name__=='__main__':
threadCount = 100
bkLock = BakeryLock(threadCount)
threads = []
for i in range(threadCount):
t = threading.Thread(target=start_request, args=(i, bkLock,))
t.start()
threads.append(t)
for i in range(threadCount):
threads[i].join()
print(incNum)