這些技巧可能大家大部分都用過了，如果用過就當作加深點映像，如果沒有遇到過，就當作學會了幾個技巧。
1、 確保數組值
使用 grid ，需要重新創建原始數據，並且每行的列長度可能不匹配， 爲了確保不匹配行之間的長度相等，可以使用Array.fill方法。
let array = Array(5).fill('');
console.log(array); // outputs (5) ["", "", "", "", ""]
2.獲取數組唯一值
ES6 提供了從數組中提取惟一值的兩種非常簡潔的方法。不幸的是，它們不能很好地處理非基本類型的數組。在本文中，主要關注基本數據類型。
const cars = [
'Mazda',
'Ford',
'Renault',
'Opel',
'Mazda'
]
const uniqueWithArrayFrom = Array.from(new Set(cars));
console.log(uniqueWithArrayFrom); // outputs ["Mazda", "Ford", "Renault", "Opel"]
const uniqueWithSpreadOperator = [...new Set(cars)];
console.log(uniqueWithSpreadOperator);// outputs ["Mazda", "Ford", "Renault", "Opel"]
3.使用展開運算符合並對象和對象數組
對象合併是很常見的事情，我們可以使用新的ES6特性來更好，更簡潔的處理合並的過程。
// merging objects
const product = { name: 'Milk', packaging: 'Plastic', price: '5$' }
const manufacturer = { name: 'Company Name', address: 'The Company Address' }
const productManufacturer = { ...product, ...manufacturer };
console.log(productManufacturer);
// outputs { name: "Company Name", packaging: "Plastic", price: "5$", address: "The Company Address" }
// merging an array of objects into one
const cities = [
{ name: 'Paris', visited: 'no' },
{ name: 'Lyon', visited: 'no' },
{ name: 'Marseille', visited: 'yes' },
{ name: 'Rome', visited: 'yes' },
{ name: 'Milan', visited: 'no' },
{ name: 'Palermo', visited: 'yes' },
{ name: 'Genoa', visited: 'yes' },
{ name: 'Berlin', visited: 'no' },
{ name: 'Hamburg', visited: 'yes' },
{ name: 'New York', visited: 'yes' }
];
const result = cities.reduce((accumulator, item) => {
return {
...accumulator,
[item.name]: item.visited
}
}, {});
console.log(result);
/* outputs
Berlin: "no"
Genoa: "yes"
Hamburg: "yes"
Lyon: "no"
Marseille: "yes"
Milan: "no"
New York: "yes"
Palermo: "yes"
Paris: "no"
Rome: "yes"
*/
4.、數組 map 的方法 (不使用Array.Map)
另一種數組 map 的實現的方式，不用 Array.map。
Array.from 還可以接受第二個參數，作用類似於數組的map方法，用來對每個元素進行處理，將處理後的值放入返回的數組。如下：
const cities = [
{ name: 'Paris', visited: 'no' },
{ name: 'Lyon', visited: 'no' },
{ name: 'Marseille', visited: 'yes' },
{ name: 'Rome', visited: 'yes' },
{ name: 'Milan', visited: 'no' },
{ name: 'Palermo', visited: 'yes' },
{ name: 'Genoa', visited: 'yes' },
{ name: 'Berlin', visited: 'no' },
{ name: 'Hamburg', visited: 'yes' },
{ name: 'New York', visited: 'yes' }
];
const cityNames = Array.from(cities, ({ name}) => name);
console.log(cityNames);
// outputs ["Paris", "Lyon", "Marseille", "Rome", "Milan", "Palermo", "Genoa", "Berlin", "Hamburg", "New York"]
- 有條件的對象屬性
不再需要根據一個條件創建兩個不同的對象，可以使用展開運算符號來處理。
nst getUser = (emailIncluded) => { return { name: 'John', surname: 'Doe', ...emailIncluded && { email : '[email protected]' } }}const user = getUser(true);console.log(user); // outputs { name: "John", surname: "Doe", email: "[email protected]" }const userWithoutEmail = getUser(false);console.log(userWithoutEmail); // outputs { name: "John", surname: "Doe" }
- 解構原始數據
有時候一個對象包含很多屬性，而我們只需要其中的幾個，這裏可以使用解構方式來提取我們需要的屬性。如一個用戶對象內容如下：
const rawUser = {
name: 'John',
surname: 'Doe',
email: '[email protected]',
displayName: 'SuperCoolJohn',
joined: '2016-05-05',
image: 'path-to-the-image',
followers: 45
...
}
我們需要提取出兩個部分，分別是用戶及用戶信息，這時可以這樣做:
let user = {}, userDetails = {};
({ name: user.name, surname: user.surname, ...userDetails } = rawUser);
console.log(user); // outputs { name: "John", surname: "Doe" }
console.log(userDetails); // outputs { email: "[email protected]", displayName: "SuperCoolJohn", joined: "2016-05-05", image: "path-to-the-image", followers: 45 }
- 動態屬性名
早期，如果屬性名需要是動態的，我們首先必須聲明一個對象，然後分配一個屬性。這些日子已經過去了，有了ES6特性，我們可以做到這一點。
const dynamic = 'email';
let user = {
name: 'John',
[dynamic]: '[email protected]'
}
console.log(user); // outputs { name: "John", email: "[email protected]" }
8.字符串插值
在用例中，如果正在構建一個基於模板的helper組件，那麼這一點就會非常突出，它使動態模板連接容易得多。
const user = {
name: 'John',
surname: 'Doe',
details: {
email: '[email protected]',
displayName: 'SuperCoolJohn',
joined: '2016-05-05',
image: 'path-to-the-image',
followers: 45
}
}
const printUserInfo = (user) => {
const text = `The user is ${user.name} ${user.surname}. Email: ${user.details.email}. Display Name: ${user.details.displayName}. ${user.name} has ${user.details.followers} followers.`
console.log(text);
}
printUserInfo(user);