这些技巧可能大家大部分都用过了，如果用过就当作加深点映像，如果没有遇到过，就当作学会了几个技巧。
1、 确保数组值
使用 grid ，需要重新创建原始数据，并且每行的列长度可能不匹配， 为了确保不匹配行之间的长度相等，可以使用Array.fill方法。
let array = Array(5).fill('');
console.log(array); // outputs (5) ["", "", "", "", ""]
2.获取数组唯一值
ES6 提供了从数组中提取惟一值的两种非常简洁的方法。不幸的是，它们不能很好地处理非基本类型的数组。在本文中，主要关注基本数据类型。
const cars = [
'Mazda',
'Ford',
'Renault',
'Opel',
'Mazda'
]
const uniqueWithArrayFrom = Array.from(new Set(cars));
console.log(uniqueWithArrayFrom); // outputs ["Mazda", "Ford", "Renault", "Opel"]
const uniqueWithSpreadOperator = [...new Set(cars)];
console.log(uniqueWithSpreadOperator);// outputs ["Mazda", "Ford", "Renault", "Opel"]
3.使用展开运算符合并对象和对象数组
对象合并是很常见的事情，我们可以使用新的ES6特性来更好，更简洁的处理合并的过程。
// merging objects
const product = { name: 'Milk', packaging: 'Plastic', price: '5$' }
const manufacturer = { name: 'Company Name', address: 'The Company Address' }
const productManufacturer = { ...product, ...manufacturer };
console.log(productManufacturer);
// outputs { name: "Company Name", packaging: "Plastic", price: "5$", address: "The Company Address" }
// merging an array of objects into one
const cities = [
{ name: 'Paris', visited: 'no' },
{ name: 'Lyon', visited: 'no' },
{ name: 'Marseille', visited: 'yes' },
{ name: 'Rome', visited: 'yes' },
{ name: 'Milan', visited: 'no' },
{ name: 'Palermo', visited: 'yes' },
{ name: 'Genoa', visited: 'yes' },
{ name: 'Berlin', visited: 'no' },
{ name: 'Hamburg', visited: 'yes' },
{ name: 'New York', visited: 'yes' }
];
const result = cities.reduce((accumulator, item) => {
return {
...accumulator,
[item.name]: item.visited
}
}, {});
console.log(result);
/* outputs
Berlin: "no"
Genoa: "yes"
Hamburg: "yes"
Lyon: "no"
Marseille: "yes"
Milan: "no"
New York: "yes"
Palermo: "yes"
Paris: "no"
Rome: "yes"
*/
4.、数组 map 的方法 (不使用Array.Map)
另一种数组 map 的实现的方式，不用 Array.map。
Array.from 还可以接受第二个参数，作用类似于数组的map方法，用来对每个元素进行处理，将处理后的值放入返回的数组。如下：
const cities = [
{ name: 'Paris', visited: 'no' },
{ name: 'Lyon', visited: 'no' },
{ name: 'Marseille', visited: 'yes' },
{ name: 'Rome', visited: 'yes' },
{ name: 'Milan', visited: 'no' },
{ name: 'Palermo', visited: 'yes' },
{ name: 'Genoa', visited: 'yes' },
{ name: 'Berlin', visited: 'no' },
{ name: 'Hamburg', visited: 'yes' },
{ name: 'New York', visited: 'yes' }
];
const cityNames = Array.from(cities, ({ name}) => name);
console.log(cityNames);
// outputs ["Paris", "Lyon", "Marseille", "Rome", "Milan", "Palermo", "Genoa", "Berlin", "Hamburg", "New York"]
- 有条件的对象属性
不再需要根据一个条件创建两个不同的对象，可以使用展开运算符号来处理。
nst getUser = (emailIncluded) => { return { name: 'John', surname: 'Doe', ...emailIncluded && { email : '[email protected]' } }}const user = getUser(true);console.log(user); // outputs { name: "John", surname: "Doe", email: "[email protected]" }const userWithoutEmail = getUser(false);console.log(userWithoutEmail); // outputs { name: "John", surname: "Doe" }
- 解构原始数据
有时候一个对象包含很多属性，而我们只需要其中的几个，这里可以使用解构方式来提取我们需要的属性。如一个用户对象内容如下：
const rawUser = {
name: 'John',
surname: 'Doe',
email: '[email protected]',
displayName: 'SuperCoolJohn',
joined: '2016-05-05',
image: 'path-to-the-image',
followers: 45
...
}
我们需要提取出两个部分，分别是用户及用户信息，这时可以这样做:
let user = {}, userDetails = {};
({ name: user.name, surname: user.surname, ...userDetails } = rawUser);
console.log(user); // outputs { name: "John", surname: "Doe" }
console.log(userDetails); // outputs { email: "[email protected]", displayName: "SuperCoolJohn", joined: "2016-05-05", image: "path-to-the-image", followers: 45 }
- 动态属性名
早期，如果属性名需要是动态的，我们首先必须声明一个对象，然后分配一个属性。这些日子已经过去了，有了ES6特性，我们可以做到这一点。
const dynamic = 'email';
let user = {
name: 'John',
[dynamic]: '[email protected]'
}
console.log(user); // outputs { name: "John", email: "[email protected]" }
8.字符串插值
在用例中，如果正在构建一个基于模板的helper组件，那么这一点就会非常突出，它使动态模板连接容易得多。
const user = {
name: 'John',
surname: 'Doe',
details: {
email: '[email protected]',
displayName: 'SuperCoolJohn',
joined: '2016-05-05',
image: 'path-to-the-image',
followers: 45
}
}
const printUserInfo = (user) => {
const text = `The user is ${user.name} ${user.surname}. Email: ${user.details.email}. Display Name: ${user.details.displayName}. ${user.name} has ${user.details.followers} followers.`
console.log(text);
}
printUserInfo(user);