Keras訓練網絡過程中需要實時觀察性能,mean iou不是keras自帶的評估函數,tf的又覺得不好用,自己寫了一個,經過測試沒有問題,本文記錄自定義keras mean iou評估的實現方法。
計算 IoU
用numpy計算的,作爲IoU的ground truth用作測試使用:
def iou_numpy(y_true,y_pred):
intersection = np.sum(np.multiply(y_true.astype('bool'),y_pred == 1))
union = np.sum((y_true.astype('bool')+y_pred.astype('bool'))>0)
return intersection/union
keras metric IoU
def iou_keras(y_true, y_pred):
"""
Return the Intersection over Union (IoU).
Args:
y_true: the expected y values as a one-hot
y_pred: the predicted y values as a one-hot or softmax output
Returns:
the IoU for the given label
"""
label = 1
# extract the label values using the argmax operator then
# calculate equality of the predictions and truths to the label
y_true = K.cast(K.equal(y_true, label), K.floatx())
y_pred = K.cast(K.equal(y_pred, label), K.floatx())
# calculate the |intersection| (AND) of the labels
intersection = K.sum(y_true * y_pred)
# calculate the |union| (OR) of the labels
union = K.sum(y_true) + K.sum(y_pred) - intersection
# avoid divide by zero - if the union is zero, return 1
# otherwise, return the intersection over union
return K.switch(K.equal(union, 0), 1.0, intersection / union)
計算 mean IoU
mean IoU 簡便起見,選取 (0,1,0.05) 作爲不同的IoU閾值,計算平均IoU
numpy 真實值計算
def mean_iou_numpy(y_true,y_pred):
iou_list = []
for thre in list(np.arange(0.0000001,0.99,0.05)):
y_pred_temp = y_pred >= thre
iou = iou_numpy(y_true, y_pred_temp)
iou_list.append(iou)
return np.mean(iou_list)
Keras mean IoU
def mean_iou_keras(y_true, y_pred):
"""
Return the mean Intersection over Union (IoU).
Args:
y_true: the expected y values as a one-hot
y_pred: the predicted y values as a one-hot or softmax output
Returns:
the mean IoU
"""
label = 1
# extract the label values using the argmax operator then
# calculate equality of the predictions and truths to the label
y_true = K.cast(K.equal(y_true, label), K.floatx())
mean_iou = K.variable(0)
thre_list = list(np.arange(0.0000001,0.99,0.05))
for thre in thre_list:
y_pred_temp = K.cast(y_pred >= thre, K.floatx())
y_pred_temp = K.cast(K.equal(y_pred_temp, label), K.floatx())
# calculate the |intersection| (AND) of the labels
intersection = K.sum(y_true * y_pred_temp)
# calculate the |union| (OR) of the labels
union = K.sum(y_true) + K.sum(y_pred_temp) - intersection
iou = K.switch(K.equal(union, 0), 1.0, intersection / union)
mean_iou = mean_iou + iou
return mean_iou / len(thre_list)
測試
## 隨機生成預測值
y_true_np = np.ones([10,10])
y_pred_np = np.random.rand(10,10)
## 真實IoU值
print(f' iou : {iou_numpy(y_true_np, y_pred_np)}')
print(f' mean_iou_numpy : {mean_iou_numpy(y_true_np, y_pred_np)}')
y_true = tf.Variable(y_true_np)
y_pred = tf.Variable(y_pred_np)
## 計算節點
iou_res = iou_keras (y_true, y_pred)
m_iou_res = mean_iou_keras (y_true, y_pred)
## 變量初始化
init_op = tf.global_variables_initializer()
with tf.Session() as sess:
sess.run(init_op)
## 由於存在誤差,結果在0.0000001範圍內即可認爲相同
result = sess.run(iou_res)
print(f'result : {result} \nsame with ground truth: {abs(iou_numpy(y_true_np, y_pred_np) - result)< 0.0000001}')
result = sess.run(m_iou_res)
print(f'result : {result} \nsame with ground truth: {abs(mean_iou_numpy(y_true_np, y_pred_np) - result) < 0.0000001}')
輸出:
iou : 0.0
mean_iou_numpy : 0.5295
result : 0.0
same with ground truth: True
result : 0.5295000076293945
same with ground truth: True
源碼下載
https://github.com/zywvvd/Python_Practise