32位的Int轉成長度爲4的8位Char數組

int num = 9999;

char c[4] = {0};

方法一：使用memcpy函數，需要注意大小端問題

memcpy(c, (char*)&num, 4)

結果：c[0] = 15, c[1] = 39, c[2] = 0, c[3] = 0

 

方法二：位操作

c[3] = num & 0xFF;

num = num >> 8;

c[2] = num & 0xFF;

num = num >> 8;

c[1] = num & 0xFF;

num = num >> 8;

c[0] == num & oxFF;

結果： 

c[0] = 0, c[1] = 0, c[2] = 39, c[3] = 15