LeetCode 178. Rank Scores

Description:

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no “holes” between ranks.

±—±------+
| Id | Score |
±—±------+
| 1 | 3.50 |
| 2 | 3.65 |
| 3 | 4.00 |
| 4 | 3.85 |
| 5 | 4.00 |
| 6 | 3.65 |
±—±------+
For example, given the above Scores table, your query should generate the following report (order by highest score):

±------±-----+
| Score | Rank |
±------±-----+
| 4.00 | 1 |
| 4.00 | 1 |
| 3.85 | 2 |
| 3.65 | 3 |
| 3.65 | 3 |
| 3.50 | 4 |
±------±-----+

Solution:

從Scores中選出不重複的數據值，對於外面每個Score查詢，比較S>=Score的次數（此爲每個Score排名數）

# Write your MySQL query statement below
Select 
Score,
(SELECT COUNT(*) FROM 
        (SELECT DISTINCT Score as S FROM Scores)  as temp
WHERE S >= Score
) as "Rank"
FROM Scores
ORDER BY Score DESC