package com.lgx.jdk8.part02;
import java.util.*;
import java.util.stream.Collectors;
import java.util.stream.IntStream;
import java.util.stream.Stream;
/**
* Stream的使用介紹
*/
public class Test04Stream {
public static void main(String[] args) {
//創建流的幾種方式
Stream stream1 = Stream.of("hello", "world", "hello world");
String[] myArray = new String[]{"hello", "world", "hello world"};
Stream stream2 = Stream.of(myArray);
Stream stream3 = Arrays.stream(myArray);
List<String> myList = Arrays.asList("hello", "world", "hello world");
Stream stream4 = myList.stream();
System.out.println("------------------------");
//IntStream的使用
IntStream.of(new int[]{3,4,5,6,7}).forEach(System.out::print);System.out.println();
IntStream.range(3,8).forEach(System.out::print);System.out.println();
IntStream.rangeClosed(3,7).forEach(System.out::print);System.out.println();
System.out.println("------------------------");
//每個數乘以2再求和
List<Integer> list = Arrays.asList(1,2,3,4,5,6,7,8,9);
//傳統寫法
/*int sum = 0;
for(Integer integer: list){
sum += integer*2;
}
System.out.println("sum = [" + sum + "]");*/
//jdk8寫法
System.out.println("sum = [" + list.stream().map(i -> i*2).reduce(0, Integer::sum) + "]");
//流轉換成集合,再遍歷
Stream<String> streams = Stream.of("hello", "world", "hello world");
/*String[] strArray = streams.toArray(length -> new String[length]);
Arrays.asList(strArray).forEach(System.out::println);*/
//用方法引用來寫
/*String[] strArray2 = streams.toArray(String[]::new);
Arrays.asList(strArray2).forEach(System.out::println);*/
//用collect(),另外方法來寫
/*List<String> strList = streams.collect(() -> new ArrayList(), (theList, item) -> theList.add(item),
(theList1, theList2) -> theList1.addAll(theList2));
strList.forEach(System.out::println);*/
//用collect(),參數方法引用來寫
/*List<String> strList2 = streams.collect(ArrayList::new, ArrayList::add, ArrayList::addAll);
strList2.forEach(System.out::println);*/
//用collect()配合Collectors.toList()來寫
/*List<String> strList3 = streams.collect(Collectors.toList());
strList3.forEach(System.out::println);*/
//用collect()配合Collectors.toCollection來寫,可以指定類型:如ArrayList,LinkList等
/*List<String> strList4 = streams.collect(Collectors.toCollection(ArrayList::new));
strList4.forEach(System.out::println);*/
//轉換成set
/*Set<String> set = streams.collect(Collectors.toSet());
set.forEach(System.out::println);
System.out.println("set type = [" + set.getClass() + "]");*/
//轉換成set,指定類型
/*Set<String> set = streams.collect(Collectors.toCollection(TreeSet::new));
set.forEach(System.out::println);
System.out.println("set type = [" + set.getClass() + "]");*/
//拼接
/*String str = streams.collect(Collectors.joining());
System.out.println("拼接str=" + str);*/
/*String str = streams.collect(Collectors.joining(", "));
System.out.println("拼接str2=" + str);*/
/*String str = streams.collect(Collectors.joining(", ", "[", "]"));
System.out.println("拼接str3=" + str);*/
//過濾,將每個參數由小寫變成大寫,map函數就是映射,針對每一個元素
List<String> list2 = Arrays.asList("hello", "world", "hello world");
list2.stream().map(String::toUpperCase).collect(Collectors.toList()).forEach(System.out::println);
//過濾,將每個參數變成之前的平方
List<Integer> list3 = Arrays.asList(2,3,4,5);
list3.stream().map(item -> item * item).collect(Collectors.toList()).forEach(System.out::println);
System.out.println("==========================");
//flatMap操作,扁平化map,會將裏面的集合元素,合併到一個集合
Stream<List<Integer>> stream5 = Stream.of(Arrays.asList(1,2,3), Arrays.asList(13,14), Arrays.asList(25,26,27));
stream5.flatMap(theList -> theList.stream()).map(item -> item * item).forEach(System.out::println);
/**
* generate方法使用
* findFirst之所以返回一個Optional,是因爲避免NPE(空指針異常),因爲可能一個都沒找到
*/
Stream<String> stream6 = Stream.generate(UUID.randomUUID()::toString);
stream6.findFirst().ifPresent(System.out::println);
//iterate方法使用
Stream.iterate(1, item -> item + 2).limit(10).forEach(System.out::println);
//找出上面那個流中大於2的元素,然後將每個元素乘以3,然後忽略掉前4個元素,然後再取出流中的前5個元素,最後求出流中元素的總和
//mapToInt是map的一個具化,省去類型轉換,skip標示忽略掉前幾個元素,limit是取幾個元素
Stream<Integer> stream7 = Stream.iterate(1, item -> item + 2).limit(10);
/*int sum = stream7.filter(item -> item > 2).mapToInt(item -> item * 3).skip(4).limit(5).sum();
System.out.println("sum=" + sum);*/
//如果是求最大值
/*OptionalInt max = stream7.filter(item -> item > 2).mapToInt(item -> item * 3).skip(4).limit(5).max();
max.ifPresent(System.out::print);*/
//如果我們又想求總和,或者最大值,最小值,平均值,個數之類的應該怎麼寫呢
//summaryStatistics是總結統計的,是一個終止操作
IntSummaryStatistics intSummaryStatistics = stream7.filter(item -> item > 2).mapToInt(item -> item * 3).skip(4).limit(5).summaryStatistics();
System.out.println("sum = [" + intSummaryStatistics.getSum() + "]");
System.out.println("max = [" + intSummaryStatistics.getMax() + "]");
System.out.println("min = [" + intSummaryStatistics.getMin() + "]");
System.out.println("ave = [" + intSummaryStatistics.getAverage() + "]");
System.out.println("count = [" + intSummaryStatistics.getCount() + "]");
//Stream的使用陷阱
Stream<Integer> stream8 = Stream.iterate(1, item -> item + 2).limit(10); /*System.out.println("stream8 = " + stream8); System.out.println("stream8 = " + stream8.filter(item -> item > 2)); System.out.println("stream8 = " + stream8.distinct());//distinct去重的作用*/ //執行2個操作,會報錯,流一旦被關閉了就不能再去操作了,或者被操作了一次之後,在另外一個地方又重新去操作, //規避辦法如下,當然最好寫成鏈的形式 System.out.println("stream8 = " + stream8); Stream<Integer> stream8_2 = stream8.filter(item -> item > 2); System.out.println("stream8_2 = " + stream8_2); Stream<Integer> stream8_3 = stream8_2.distinct(); System.out.println("stream8_3 = " + stream8_3); List<String> list4 = Arrays.asList("hello", "world", "hello world"); //正常打印 //list4.stream().map(item -> item.substring(0, 1) + item.substring(2)).forEach(System.out::println); //啥都不打印,因爲沒有及早求值或者沒有終止操作 /*list4.stream().map(item ->{ String result = item.substring(0, 1) + item.substring(2); System.out.println("test-------"); return result; });*/ //依次打印一個test,再輸出一個元素 /*list4.stream().map(item ->{ String result = item.substring(0, 1) + item.substring(2); System.out.println("test-------"); return result; }).forEach(System.out::println);*/ //關於執行順序 //IntStream.iterate(0, i -> (i+1)%2).limit(10).distinct().forEach(System.out::println);//limit已經定義了個數,再去重,就不會無限循環 //IntStream.iterate(0, i -> (i+1)%2).distinct().limit(10).forEach(System.out::println);//無限循環,因爲distinct會一直等待前面的數字
}}