公司面試題——線程數組求和

編程題：
 說明：1)用多線程的方式對inputs數組的每個元素作求和運算，例如某個元素爲45，則計算：1+2+3+....+45
       2)把計算結果放到outputs數組對應的索引的位置，例如:
        inputs爲：2,3,0,1 計算後outputs爲：3,6,0,1
        假定：outputs和inputs數組的元素個數一樣
        完成後，程序的最後會打印輸入和正確的結果各一行上

實現代碼：

package com.image.common.util;

import java.util.ArrayList;
import java.util.List;

public class TestMain {
    public static void main(String[] args) {
        int[] inputs = new int[]{2,3,0,1};
        int[] outputs = new int[inputs.length];

        List<TestThread> list = new ArrayList<TestThread>();
        TestThread temp = null;
        for(int i=0;i<inputs.length;i++){
            temp = new TestThread(inputs[i]);
            list.add(temp);
            temp.start();
        }
        for (int i = 0; i < list.size(); i++) {
            try {
                list.get(i).join();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }

        String result = "";
        for (int i = 0; i < list.size(); i++) {
            outputs[i] = list.get(i).getResult();
            result = result + outputs[i] + ",";
        }
        System.out.println("結果:"+result);
    }
}

class TestThread extends Thread{

    private int operation;
    private int result;

    public TestThread(int operation){
        this.operation = operation;
    }

    public void run() {
        for (int i = 1; i <= operation; i++) {
            result += i ;
        }
    }

    public int getOperation() {
        return operation;
    }

    public void setOperation(int operation) {
        this.operation = operation;
    }

    public int getResult() {
        return result;
    }

    public void setResult(int result) {
        this.result = result;
    }
}