公司面试题——线程数组求和

编程题：
 说明：1)用多线程的方式对inputs数组的每个元素作求和运算，例如某个元素为45，则计算：1+2+3+....+45
       2)把计算结果放到outputs数组对应的索引的位置，例如:
        inputs为：2,3,0,1 计算后outputs为：3,6,0,1
        假定：outputs和inputs数组的元素个数一样
        完成后，程序的最后会打印输入和正确的结果各一行上

实现代码：

package com.image.common.util;

import java.util.ArrayList;
import java.util.List;

public class TestMain {
    public static void main(String[] args) {
        int[] inputs = new int[]{2,3,0,1};
        int[] outputs = new int[inputs.length];

        List<TestThread> list = new ArrayList<TestThread>();
        TestThread temp = null;
        for(int i=0;i<inputs.length;i++){
            temp = new TestThread(inputs[i]);
            list.add(temp);
            temp.start();
        }
        for (int i = 0; i < list.size(); i++) {
            try {
                list.get(i).join();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }

        String result = "";
        for (int i = 0; i < list.size(); i++) {
            outputs[i] = list.get(i).getResult();
            result = result + outputs[i] + ",";
        }
        System.out.println("结果:"+result);
    }
}

class TestThread extends Thread{

    private int operation;
    private int result;

    public TestThread(int operation){
        this.operation = operation;
    }

    public void run() {
        for (int i = 1; i <= operation; i++) {
            result += i ;
        }
    }

    public int getOperation() {
        return operation;
    }

    public void setOperation(int operation) {
        this.operation = operation;
    }

    public int getResult() {
        return result;
    }

    public void setResult(int result) {
        this.result = result;
    }
}