eclipse可自動建立結構，但是自己手動建立會更加熟悉
1.創建初始界面
找到Tomcat安裝目錄，在webapps目錄下創建項目名，進入項目下，創建啓動界面index.html
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>My JSP 'index.jsp' starting page</title>
</head>
<body>
This is my JSP page2. <br>
<form method="post" action="selectBeer.do">
<p>Select beer characteristics</p>
Color:
<select name="color" size="1">
<option>light</option>
<option>amber</option>
<option>brown</option>
<option>dark</option>
</select>
<br><br>
<center>
<input type="submit"/>
</center>
</form>
</body>
</html>2.寫web.xml配置文件
在項目目錄下創建WEB-INF目錄，在該目錄下再創建web.xml
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
version="2.4">
<servlet>
<servlet-name>CH3 Beer</servlet-name>
<servlet-class>com.example.web.BeerSelect</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>CH3 Beer</servlet-name>
<url-pattern>/SelectBeer.do</url-pattern>
</servlet-mapping>
</web-app>package com.example.web;
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
public class BeerSelect extends HttpServlet{
public void doPost(HttpServletRequest request,
HttpServletResponse response)throws IOException,ServletException
{
response.setContentType("text/html");
PrintWriter out=response.getWriter();
out.println("Beer Selection Advice<br>");
String c=request.getParameter("color");
out.println("<br>Got beer color "+c);
}
}javac -classpath +servlet-api.jar的路徑+ 該java程序將編譯好的.class文件放到 項目名/WEB-INF/classes/com/example/web/目錄下