1. 數組
創建一個數組
public class Mode3 {
public static void main(String[] args) {
int[] arr1 = new int[3];
System.out.println(arr1);
arr1 = new int[4];
System.out.println(arr1);
}
}
2. 遍歷數組
package mode4;
public class Mode4 {
public static void main(String[] args) {
int[] arr = { 1, 2, 3, 4, 5, 6, 7, 8 };
for (int a = 0; a < arr.length; a++) {
System.out.println(arr[a]);
}
}
}
3. 取出數組中的最大值
package mode4;
public class Mode4 {
public static void main(String[] args) {
System.out.println(getMax());
}
public static int getMax() {
int a = 0;
int[] arr = { 12, 3, 4, 5, 6, 7, 5, 446, 46, 4684, 68 };
for (int i = 0; i < arr.length; i++) {
// 找一個變量來暫時存儲數組中較大的值,直到遍歷完打印即可
if (arr[i] > a) {
a = arr[i];
} else {
a = a;
}
}
return a;
}
}
4. 數組元素反轉
1.使用兩個數組,直接顛倒
package mode4;
public class Mode5 {
public static void main(String[] args) {
// 數組的反轉
int[] arr = { 1, 2, 3, 4, 5, 6 };
int[] arr0 = new int[arr.length];
for (int i = 0; i < arr.length; i++) {
arr0[i] = arr[arr.length-(i+1)];
}
for (int i = 0; i < arr0.length; i++) {
System.out.println(arr0[i]);
}
}
}
- 使用第三個空變量進行值的傳遞
package mode4;
public class Mode5 {
public static void main(String[] args) {
getChange();
}
public static void getChange() {
int[] arr1 = { 1, 2, 3, 4, 5, 6, 7, 8, 9 };
int temp;
for (int i = 0; i < (arr1.length) / 2; i++) {
//外部循環不能到全部的數組,因爲全部遍歷就都換了,所以要留下一半不要換
temp = arr1[i];
arr1[i] = arr1[arr1.length - 1 - i];
arr1[arr1.length - 1 - i] = temp;
}
for (int i = 0; i < arr1.length; i++) {
System.out.println(arr1[i]);
}
}
}
5. 定義方法以數字作爲返回值
package mode4;
public class Mode6 {
public static void main(String[] args) {
System.out.println(getArr()[1]);
}
public static int[] getArr() {
int a = 10;
int b = 20;
int[] arr = new int[] { a, b };
return arr;
}
}
任何數據類型都可以作爲返回值。