大數據學習，Hive是丟不掉的！Hive練習題50道，你也試試！

建表

create table student(s_id string,s_name string,s_birth string,s_sex string) row format delimited fields terminated by '\t';

create table course(c_id string,c_name string,t_id string) row format delimited fields terminated by '\t';

create table teacher(t_id string,t_name string) row format delimited fields terminated by '\t';

create table score(s_id string,c_id string,s_score int) row format delimited fields terminated by '\t';

 

生成數據

vi /export/data/hivedatas/student.csv

01 趙雷 1990-01-01 男
02 錢電 1990-12-21 男
03 孫風 1990-05-20 男
04 李雲 1990-08-06 男
05 周梅 1991-12-01 女
06 吳蘭 1992-03-01 女
07 鄭竹 1989-07-01 女
08 王菊 1990-01-20 女

vi /export/data/hivedatas/course.csv

01  語文  02
02  數學  01
03  英語  03

vi /export/data/hivedatas/teacher.csv

01  張三
02  李四
03  王五

vi /export/data/hivedatas/score.csv

01  01  80
01  02  90
01  03  99
02  01  70
02  02  60
02  03  80
03  01  80
03  02  80
03  03  80
04  01  50
04  02  30
04  03  20
05  01  76
05  02  87
06  01  31
06  03  34
07  02  89
07  03  98

導數據到hive

load data local inpath '/export/data/hivedatas/student.csv' into table student;

load data local inpath '/export/data/hivedatas/course.csv' into table course;

load data local inpath '/export/data/hivedatas/teacher.csv' into table teacher;

load data local inpath '/export/data/hivedatas/score.csv' into table score;

–注:–hive查詢語法

SELECT [ALL | DISTINCT] select_expr, select_expr, ...
    FROM table_reference
    [WHERE where_condition]
    [GROUP BY col_list [HAVING condition]]
    [CLUSTER BY col_list
      | [DISTRIBUTE BY col_list] [SORT BY| ORDER BY col_list]
    ]
    [LIMIT number]

– 1、查詢"01"課程比"02"課程成績高的學生的信息及課程分數:

select student.*,a.s_score as 01_score,b.s_score as 02_score
from student
  join score a on student.s_id=a.s_id and a.c_id='01'
  left join score b on student.s_id=b.s_id and b.c_id='02'
where  a.s_score>b.s_score;

–答案2

select student.*,a.s_score as 01_score,b.s_score as 02_score
from student
join score a on  a.c_id='01'
join score b on  b.c_id='02'
where  a.s_id=student.s_id and b.s_id=student.s_id and a.s_score>b.s_score;

– 2、查詢"01"課程比"02"課程成績低的學生的信息及課程分數:

select student.*,a.s_score as 01_score,b.s_score as 02_score
from student
join score a on student.s_id=a.s_id and a.c_id='01'
left join score b on student.s_id=b.s_id and b.c_id='02'
where a.s_score<b.s_score;

–答案2

select student.*,a.s_score as 01_score,b.s_score as 02_score
from student
join score a on  a.c_id='01'
join score b on  b.c_id='02'
where  a.s_id=student.s_id and b.s_id=student.s_id and a.s_score<b.s_score;

– 3、查詢平均成績大於等於60分的同學的學生編號和學生姓名和平均成績:

select  student.s_id,student.s_name,tmp.平均成績 from student
  join (
    select score.s_id,round(avg(score.s_score),1)as 平均成績
        from score group by s_id)as tmp
  on tmp.平均成績>=60
where student.s_id = tmp.s_id

–答案2

select  student.s_id,student.s_name,round(avg (score.s_score),1) as 平均成績 from student
join score on student.s_id = score.s_id
group by student.s_id,student.s_name
having avg (score.s_score) >= 60;

– 4、查詢平均成績小於60分的同學的學生編號和學生姓名和平均成績:
– (包括有成績的和無成績的)

select  student.s_id,student.s_name,tmp.avgScore from student
join (
select score.s_id,round(avg(score.s_score),1)as avgScore from score group by s_id)as tmp
on tmp.avgScore < 60
where student.s_id=tmp.s_id
union all
select  s2.s_id,s2.s_name,0 as avgScore from student s2
where s2.s_id not in
    (select distinct sc2.s_id from score sc2);

–答案2

select  score.s_id,student.s_name,round(avg (score.s_score),1) as avgScore from student
inner join score on student.s_id=score.s_id
group by score.s_id,student.s_name
having avg (score.s_score) < 60
union all
select  s2.s_id,s2.s_name,0 as avgScore from student s2
where s2.s_id not in
    (select distinct sc2.s_id from score sc2);

– 5、查詢所有同學的學生編號、學生姓名、選課總數、所有課程的總成績:

select student.s_id,student.s_name,(count(score.c_id) )as total_count,sum(score.s_score)as total_score
from student
left join score on student.s_id=score.s_id
group by student.s_id,student.s_name ;

– 6、查詢"李"姓老師的數量:

select t_name,count(1) from teacher  where t_name like '李%' group by t_name;

– 7、查詢學過"張三"老師授課的同學的信息:

select student.* from student
join score on student.s_id =score.s_id
join  course on course.c_id=score.c_id
join  teacher on course.t_id=teacher.t_id and t_name='張三';

– 8、查詢沒學過"張三"老師授課的同學的信息:

select student.* from student
left join (select s_id from score
      join  course on course.c_id=score.c_id
      join  teacher on course.t_id=teacher.t_id and t_name='張三')tmp
on  student.s_id =tmp.s_id
where tmp.s_id is null;

– 9、查詢學過編號爲"01"並且也學過編號爲"02"的課程的同學的信息:

select * from student
join (select s_id from score where c_id =1 )tmp1
    on student.s_id=tmp1.s_id
join (select s_id from score where c_id =2 )tmp2
    on student.s_id=tmp2.s_id;

– 10、查詢學過編號爲"01"但是沒有學過編號爲"02"的課程的同學的信息:

select student.* from student
join (select s_id from score where c_id =1 )tmp1
    on student.s_id=tmp1.s_id
left join (select s_id from score where c_id =2 )tmp2
    on student.s_id =tmp2.s_id
where tmp2.s_id is null;

– 11、查詢沒有學全所有課程的同學的信息:
–先查詢出課程的總數量

   select count(1) from course;

–再查詢所需結果

select student.* from student
left join(
      select s_id
        from score
          group by s_id
            having count(c_id)=3)tmp
on student.s_id=tmp.s_id
where tmp.s_id is null;

–方法二(一步到位):

select student.* from student
join (select count(c_id)num1 from course)tmp1
left join(
      select s_id,count(c_id)num2
        from score group by s_id)tmp2
on student.s_id=tmp2.s_id and tmp1.num1=tmp2.num2
where tmp2.s_id is null;

– 12、查詢至少有一門課與學號爲"01"的同學所學相同的同學的信息:

select student.* from student
join (select c_id from score where score.s_id=01)tmp1
join (select s_id,c_id from score)tmp2
    on tmp1.c_id =tmp2.c_id and student.s_id =tmp2.s_id
where student.s_id  not in('01')
group by student.s_id,s_name,s_birth,s_sex;

– 13、查詢和"01"號的同學學習的課程完全相同的其他同學的信息:
–備註:hive不支持group_concat方法,可用 concat_ws(’|’, collect_set(str)) 實現

select student.*,tmp1.course_id from student
join (select s_id ,concat_ws('|', collect_set(c_id)) course_id from score
      group by s_id having s_id not in (1))tmp1
  on student.s_id = tmp1.s_id
join (select concat_ws('|', collect_set(c_id)) course_id2
            from score  where s_id=1)tmp2
      on tmp1.course_id = tmp2.course_id2;

– 14、查詢沒學過"張三"老師講授的任一門課程的學生姓名:

select student.* from student
  left join (select s_id from score
          join (select c_id from course join  teacher on course.t_id=teacher.t_id and t_name='張三')tmp2
          on score.c_id=tmp2.c_id )tmp
  on student.s_id = tmp.s_id
  where tmp.s_id is null;

– 15、查詢兩門及其以上不及格課程的同學的學號，姓名及其平均成績:

select student.s_id,student.s_name,tmp.avg_score from student
inner join (select s_id from score
      where s_score<60
        group by score.s_id having count(s_id)>1)tmp2
on student.s_id = tmp2.s_id
left join (
    select s_id,round(AVG (score.s_score)) avg_score
      from score group by s_id)tmp
      on tmp.s_id=student.s_id;

– 16、檢索"01"課程分數小於60，按分數降序排列的學生信息:

select student.*,s_score from student,score
where student.s_id=score.s_id and s_score<60 and c_id='01'
order by s_score desc;

– 17、按平均成績從高到低顯示所有學生的所有課程的成績以及平均成績:

select a.s_id,tmp1.s_score as chinese,tmp2.s_score as math,tmp3.s_score as english,
    round(avg (a.s_score),2) as avgScore
from score a
left join (select s_id,s_score  from score s1 where  c_id='01')tmp1 on  tmp1.s_id=a.s_id
left join (select s_id,s_score  from score s2 where  c_id='02')tmp2 on  tmp2.s_id=a.s_id
left join (select s_id,s_score  from score s3 where  c_id='03')tmp3 on  tmp3.s_id=a.s_id
group by a.s_id,tmp1.s_score,tmp2.s_score,tmp3.s_score order by avgScore desc;

– 18.查詢各科成績最高分、最低分和平均分：以如下形式顯示：課程ID，課程name，最高分，最低分，平均分，及格率，中等率，優良率，優秀率:
–及格爲>=60，中等爲：70-80，優良爲：80-90，優秀爲：>=90

select course.c_id,course.c_name,tmp.maxScore,tmp.minScore,tmp.avgScore,tmp.passRate,tmp.moderate,tmp.goodRate,tmp.excellentRates from course
join(select c_id,max(s_score) as maxScore,min(s_score)as minScore,
    round(avg(s_score),2) avgScore,
    round(sum(case when s_score>=60 then 1 else 0 end)/count(c_id),2)passRate,
    round(sum(case when s_score>=60 and s_score<70 then 1 else 0 end)/count(c_id),2) moderate,
    round(sum(case when s_score>=70 and s_score<80 then 1 else 0 end)/count(c_id),2) goodRate,
    round(sum(case when s_score>=80 and s_score<90 then 1 else 0 end)/count(c_id),2) excellentRates
from score group by c_id)tmp on tmp.c_id=course.c_id;

– 19、按各科成績進行排序，並顯示排名:
– row_number() over()分組排序功能(mysql沒有該方法)

select s1.*,row_number()over(order by s1.s_score desc) Ranking
    from score s1 where s1.c_id='01'order by noRanking asc
union all select s2.*,row_number()over(order by s2.s_score desc) Ranking
    from score s2 where s2.c_id='02'order by noRanking asc
union all select s3.*,row_number()over(order by s3.s_score desc) Ranking
    from score s3 where s3.c_id='03'order by noRanking asc;

– 20、查詢學生的總成績並進行排名:

select score.s_id,s_name,sum(s_score) sumscore,row_number()over(order by sum(s_score) desc) Ranking
  from score ,student
    where score.s_id=student.s_id
    group by score.s_id,s_name order by sumscore desc;

– 21、查詢不同老師所教不同課程平均分從高到低顯示:
– 方法1

select course.c_id,course.t_id,t_name,round(avg(s_score),2)as avgscore from course    join teacher on teacher.t_id=course.t_id    join score on course.c_id=score.c_id    group by course.c_id,course.t_id,t_name order by avgscore desc;

– 方法2

select course.c_id,course.t_id,t_name,round(avg(s_score),2)as avgscore from course,teacher,score   where teacher.t_id=course.t_id and course.c_id=score.c_id    group by course.c_id,course.t_id,t_name order by avgscore desc;

– 22、查詢所有課程的成績第2名到第3名的學生信息及該課程成績:

select tmp1.* from    (select * from score where c_id='01' order by s_score desc limit 3)tmp1    order by s_score asc limit 2union all select tmp2.* from    (select * from score where c_id='02' order by s_score desc limit 3)tmp2    order by s_score asc limit 2union all select tmp3.* from    (select * from score where c_id='03' order by s_score desc limit 3)tmp3    order by s_score asc limit 2;

– 23、統計各科成績各分數段人數：課程編號,課程名稱,[100-85],[85-70],[70-60],[0-60]及所佔百分比

select c.c_id,c.c_name,tmp1.s0_60, tmp1.percentum,tmp2.s60_70, tmp2.percentum,tmp3.s70_85, 

tmp3.percentum,tmp4.s85_100, tmp4.percentumfrom course cjoin(select c_id,sum(case when s_score<60 then 1 else 0 end )as s0_60,               round(100*sum(case when s_score<60 then 1 else 0 end )/count(c_id),2)as percentum     from score group by c_id)tmp1 on tmp1.c_id =c.c_idleft join(select c_id,sum(case when s_score<70 and s_score>=60 then 1 else 0 end )as s60_70,               round(100*sum(case when s_score<70 and s_score>=60 then 1 else 0 end )/count(c_id),2)as percentum     from score group by c_id)tmp2 on tmp2.c_id =c.c_idleft join(select c_id,sum(case when s_score<85 and s_score>=70 then 1 else 0 end )as s70_85,               round(100*sum(case when s_score<85 and s_score>=70 then 1 else 0 end )/count(c_id),2)as percentum     from score group by c_id)tmp3 on tmp3.c_id =c.c_idleft join(select c_id,sum(case when s_score>=85 then 1 else 0 end )as s85_100,               round(100*sum(case when s_score>=85 then 1 else 0 end )/count(c_id),2)as percentum     from score group by c_id)tmp4 on tmp4.c_id =c.c_id;

– 24、查詢學生平均成績及其名次:

select tmp.*,row_number()over(order by tmp.avgScore desc) Ranking from  (select student.s_id,          student.s_name,          round(avg(score.s_score),2) as avgScore  from student join score  on student.s_id=score.s_id  group by student.s_id,student.s_name)tmporder by avgScore desc;

– 25、查詢各科成績前三名的記錄

–課程id爲01的前三名

select score.c_id,course.c_name,student.s_name,s_score from scorejoin student on student.s_id=score.s_idjoin course on  score.c_id='01' and course.c_id=score.c_idorder by s_score desc limit 3;  

–課程id爲02的前三名

 

select score.c_id,course.c_name,student.s_name,s_score from scorejoin student on student.s_id=score.s_idjoin course on  score.c_id='02' and course.c_id=score.c_idorder by s_score desc limit 3; 

–課程id爲03的前三名

 

select score.c_id,course.c_name,student.s_name,s_score from scorejoin student on student.s_id=score.s_idjoin course on  score.c_id='03' and course.c_id=score.c_id  order by s_score desc limit 3;

– 26、查詢每門課程被選修的學生數:

 

select c.c_id,c.c_name,tmp.number from course c    join (select c_id,count(1) as number from score        where score.s_score<60 group by score.c_id)tmp    on tmp.c_id=c.c_id;

– 27、查詢出只有兩門課程的全部學生的學號和姓名:

select st.s_id,st.s_name from student st  join (select s_id from score group by s_id having count(c_id) =2)tmp    on st.s_id=tmp.s_id;

– 28、查詢男生、女生人數:

select tmp1.man,tmp2.women from    (select count(1) as man from student where s_sex='男')tmp1,    (select count(1) as women from student where s_sex='女')tmp2;

– 29、查詢名字中含有"風"字的學生信息:

 

select * from student where s_name like '%風%';

– 30、查詢同名同性學生名單，並統計同名人數:

 

select s1.s_id,s1.s_name,s1.s_sex,count(*) as sameNamefrom student s1,student s2where s1.s_name=s2.s_name and s1.s_id<>s2.s_id and s1.s_sex=s2.s_sexgroup by s1.s_id,s1.s_name,s1.s_sex;

– 31、查詢1990年出生的學生名單:

 

select * from student where s_birth like '1990%';

– 32、查詢每門課程的平均成績，結果按平均成績降序排列，平均成績相同時，按課程編號升序排列:

select score.c_id,c_name,round(avg(s_score),2) as avgScore from score  join course on score.c_id=course.c_id    group by score.c_id,c_name order by avgScore desc,score.c_id asc;

– 33、查詢平均成績大於等於85的所有學生的學號、姓名和平均成績:

select score.s_id,s_name,round(avg(s_score),2)as avgScore from score    join student on student.s_id=score.s_id    group by score.s_id,s_name having avg(s_score) >= 85;

– 34、查詢課程名稱爲"數學"，且分數低於60的學生姓名和分數:

 

select s_name,s_score as mathScore from student    join (select s_id,s_score            from score,course            where score.c_id=course.c_id and c_name='數學')tmp    on tmp.s_score < 60 and student.s_id=tmp.s_id;

– 35、查詢所有學生的課程及分數情況:

select a.s_name,    SUM(case c.c_name when '語文' then b.s_score else 0 end ) as chainese,    SUM(case c.c_name when '數學' then b.s_score else 0 end ) as math,    SUM(case c.c_name when '英語' then b.s_score else 0 end ) as english,    SUM(b.s_score) as sumScore  from student a    join score b on a.s_id=b.s_id    join course c on b.c_id=c.c_id    group by s_name,a.s_id;

– 36、查詢任何一門課程成績在70分以上的學生姓名、課程名稱和分數:

select student.s_id,s_name,c_name,s_score from student  join (select sc.* from score sc        left join(select s_id from score where s_score < 70 group by s_id)tmp        on sc.s_id=tmp.s_id where tmp.s_id is null)tmp2    on student.s_id=tmp2.s_id  join course on tmp2.c_id=course.c_idorder by s_id;

**-- 查詢全部及格的信息**select sc.* from score sc  left join(select s_id from score where s_score < 60 group by s_id)tmp    on sc.s_id=tmp.s_idwhere  tmp.s_id is  null;**-- 或(效率低)**select sc.* from score scwhere sc.s_id not in (select s_id from score where s_score < 60 group by s_id);

– 37、查詢課程不及格的學生:

select s_name,c_name as courseName,tmp.s_scorefrom studentjoin (select s_id,s_score,c_name      from score,course      where score.c_id=course.c_id and s_score < 60)tmpon student.s_id=tmp.s_id;

–38、查詢課程編號爲01且課程成績在80分以上的學生的學號和姓名:

select student.s_id,s_name,s_score as score_01from studentjoin score on student.s_id=score.s_idwhere c_id='01' and s_score >= 80;

– 39、求每門課程的學生人數:

select course.c_id,course.c_name,count(1)as selectNumfrom coursejoin score on course.c_id=score.c_idgroup by course.c_id,course.c_name;

– 40、查詢選修"張三"老師所授課程的學生中，成績最高的學生信息及其成績:

select student.*,tmp3.c_name,tmp3.maxScorefrom (select s_id,c_name,max(s_score)as maxScore from score      join (select course.c_id,c_name from course join                  (select t_id,t_name from teacher where t_name='張三')tmp            on course.t_id=tmp.t_id)tmp2      on score.c_id=tmp2.c_id group by score.s_id,c_name      order by maxScore desc limit 1)tmp3join studenton student.s_id=tmp3.s_id;

– 41、查詢不同課程成績相同的學生的學生編號、課程編號、學生成績:

select distinct a.s_id,a.c_id,a.s_score from score a,score b    where a.c_id <> b.c_id and a.s_score=b.s_score;

– 42、查詢每門課程成績最好的前三名:

select tmp1.* from  (select *,row_number()over(order by s_score desc) ranking      from score  where c_id ='01')tmp1where tmp1.ranking <= 3union allselect tmp2.* from  (select *,row_number()over(order by s_score desc) ranking      from score where c_id ='02')tmp2where tmp2.ranking <= 3union allselect tmp3.* from  (select *,row_number()over(order by s_score desc) ranking      from score where c_id ='03')tmp3where tmp3.ranking <= 3;

– 43、統計每門課程的學生選修人數（超過5人的課程才統計）:
– 要求輸出課程號和選修人數，查詢結果按人數降序排列，若人數相同，按課程號升序排列

select distinct course.c_id,tmp.num from course    join (select c_id,count(1) as num from score group by c_id)tmp    where tmp.num>=5 order by tmp.num desc ,course.c_id asc;

– 44、檢索至少選修兩門課程的學生學號:

select s_id,count(c_id) as totalCoursefrom scoregroup by s_idhaving count(c_id) >= 2;

– 45、查詢選修了全部課程的學生信息:

select student.* from student,     (select s_id,count(c_id) as totalCourse       from score group by s_id)tmpwhere student.s_id=tmp.s_id and totalCourse=3;

–46、查詢各學生的年齡(週歲):
– 按照出生日期來算，當前月日 < 出生年月的月日則，年齡減一
方法一

 select s_name,s_birth,      (year(CURRENT_DATE)-year(s_birth)-        (case when month(CURRENT_DATE) < month(s_birth) then 1          when month(CURRENT_DATE) = month(s_birth) and day(CURRENT_DATE) < day(s_birth) then 1          else 0 end)        ) as age    from student;

方法二:

select s_name,s_birth,  floor((datediff(current_date,s_birth) - floor((year(current_date) - year(s_birth))/4))/365) as agefrom student;

– 47、查詢本週過生日的學生:
–方法1

 

select * from student where weekofyear(CURRENT_DATE)+1 =weekofyear(s_birth);

–方法2

select s_name,s_sex,s_birth from student    where substring(s_birth,6,2)='10'    and substring(s_birth,9,2)=14;

– 48、查詢下週過生日的學生:
–方法1

 

select * from student where weekofyear(CURRENT_DATE)+1 =weekofyear(s_birth);

–方法2

​​​​​​​​​​​​​​

select s_name,s_sex,s_birth from student    where substring(s_birth,6,2)='10'    and substring(s_birth,9,2)>=15    and substring(s_birth,9,2)<=21;

– 49、查詢本月過生日的學生:
–方法1

•  

select * from student where MONTH(CURRENT_DATE) =MONTH(s_birth);

–方法2

•  

select s_name,s_sex,s_birth from student where substring(s_birth,6,2)='10';

– 50、查詢12月份過生日的學生:

•  

select s_name,s_sex,s_birth from student where substring(s_birth,6,2)='12';