通过函数对奇数的阶乘求和
//求1!+3!+5!+……+n!的和,要求用循环嵌套设计,n<12
using System;
namespace 阶乘求和
{
class Program
{
public static int jicheng(int n)
{
int s = 1, i;
for (i = 1; i <= n; i++)
{
s = s * i;
}
return s;
}
static void Main(string[] args)
{
int s = 0,sum=0,i=1;
for (i=1;i<12;i++,i++)
{
s = Program.jicheng(i);
sum = s + sum;
}
Console.WriteLine("和为{0}",sum);
}
}
}