在Javascript對象數組中查找值[重複]

本文翻譯自：Find a value in an array of objects in Javascript [duplicate]

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Get JavaScript object from array of objects by value of property [duplicate] (17 answers) 通過屬性值從對象數組中獲取JavaScript對象[重複] （17個答案）

I know similar questions have been asked before, but this one is a little different. 我知道以前也曾問過類似的問題，但是這個問題有些不同。 I have an array of unnamed objects, which contain an array of named objects, and I need to get the object where "name" is "string 1". 我有一個未命名對象的數組，其中包含一個已命名對象的數組，我需要獲取“名稱”爲“字符串1”的對象。 Here is an example array. 這是一個示例數組。

var array = [
    { name:"string 1", value:"this", other: "that" },
    { name:"string 2", value:"this", other: "that" }
];

Update: I should have said this earlier, but once I find it, I want to replace it with an edited object. 更新：我應該早先說過，但是一旦找到它，我想用一個編輯過的對象替換它。

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#1樓

參考：https://stackoom.com/question/qI18/在Javascript對象數組中查找值-重複

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#2樓

You can do it with a simple loop: 您可以通過一個簡單的循環來做到這一點：

var obj = null;    
for (var i = 0; i < array.length; i++) {
    if (array[i].name == "string 1") {
        obj = array[i];
        break;
    }
}

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#3樓

You can loop over the array and test for that property: 您可以遍歷數組並測試該屬性：

function search(nameKey, myArray){
    for (var i=0; i < myArray.length; i++) {
        if (myArray[i].name === nameKey) {
            return myArray[i];
        }
    }
}

var array = [
    { name:"string 1", value:"this", other: "that" },
    { name:"string 2", value:"this", other: "that" }
];

var resultObject = search("string 1", array);

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#4樓

Either use a simple for -loop: 使用一個簡單的for循環：

var result = null;
for (var i = 0; i < array.length; i++) { 
  if (array[i].name === "string 1") { 
    result = array[i];
    break;
  } 
}

Or if you can, that is, if your browser supports it, use Array.filter , which is much more terse: 或者，如果可以的話，也就是說，如果您的瀏覽器支持它，請使用Array.filter ，它更簡潔：

var result = array.filter(function (obj) {
  return obj.name === "string 1";
})[0];

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#5樓

Finding the array element: 查找數組元素：

 let arr = [ { name:"string 1", value:"this", other: "that" }, { name:"string 2", value:"this", other: "that" } ]; let obj = arr.find(o => o.name === 'string 1'); console.log(obj); 

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Replacing the array element: 替換數組元素：

 let arr = [ { name:"string 1", value:"this", other: "that" }, { name:"string 2", value:"this", other: "that" } ]; let obj = arr.find((o, i) => { if (o.name === 'string 1') { arr[i] = { name: 'new string', value: 'this', other: 'that' }; return true; // stop searching } }); console.log(arr); 

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#6樓

Here is the solution for search and replace 這是搜索和替換的解決方案

function searchAndUpdate(name,replace){
    var obj = array.filter(function ( obj ) {
        return obj.name === name;
    })[0];
    obj.name = replace;
}

searchAndUpdate("string 2","New String 2");