java中靜態初始化問題

class Bowl
{
	Bowl(int maker)
	{
		System.out.println("Bowl("+maker+")");
	}
	public void f1(int maker)
	{
		System.out.println("f1("+maker+")");
	}
}
class Table
{
	static Bowl bowl1=new Bowl(1);
	Table()
	{
		System.out.println("Table");
		bowl2.f1(2);
	}
	public void f2(int maker)
	{
		System.out.println("f2("+maker+")");
	}
	static Bowl bowl2=new Bowl(2);
}
class Cupboard
{
 Bowl bowl3=new Bowl(3);
static Bowl bowl4=new Bowl(4);
	Cupboard()
	{
	System.out.println("Cupboard");
	bowl4.f1(2);
	}
	public void f3(int maker)
	{
	System.out.println("f3("+maker+")");
	}
	static Bowl bowl5=new Bowl(5);
}


class StaticOrder 
{
	public static void main(String[] args) 
	{
		System.out.println("create new Cupboard in main");
		new Cupboard();
		System.out.println("create new Cupboard in main");
		new Cupboard();
		table.f2(1);
		cup.f3(1);
		
	}
	static Table table=new Table();
	static Cupboard cup=new Cupboard();
}

輸出結果爲：

Bowl(1)
Bowl(2)
Table
f1(2)
Bowl(4)
Bowl(5)
Bowl(3)
Cupboard
f1(2)
create new Cupboard in main
Bowl(3)
Cupboard
f1(2)
create new Cupboard in main
Bowl(3)
Cupboard
f1(2)
f2(1)
f3(1)

由以上代碼可以看出初始化的順序是先靜態對象（如果他們尚未因前面的對象創建過程而被初始化），然後"非靜態"對象。靜態只被初始化一次！

下面再舉一例

class StaticOrder 
{
	public static void main(String[] args) 
	{
	/*	System.out.println("create new Cupboard in main");
		new Cupboard();
		System.out.println("create new Cupboard in main");
		new Cupboard();
		table.f2(1);
		cup.f3(1);*/
		new TestStatic().print();
		
	}
	//static Table table=new Table();
	//static Cupboard cup=new Cupboard();
}
class TestStatic
{
	TestStatic()
	{
		System.out.println("我是初始化函數");
	}
	public static void print()
	{
		System.out.println("我是靜態函數");
	}
	{
	System.out.println("我什麼也沒有");
	
	}
	static {
		System.out.println("我是靜態代碼塊");
	}
}

輸出爲:

我是靜態代碼塊
我什麼也沒有
我是初始化函數
我是靜態函數