利用sorted函數對文件名進行排序

In [5]: a = [ '../../data/facades/train/271.jpg', 
   ...:  '../../data/facades/train/272.jpg', 
   ...:  '../../data/facades/train/338.jpg', 
   ...:  '../../data/facades/train/339.jpg', 
   ...:  '../../data/facades/train/34.jpg', 
   ...:  '../../data/facades/train/340.jpg']
   
In [7]: sorted(a,key=lambda x:eval(x.split("/")[-1].split('.')[0]))                                                                                                      
Out[7]: 
['../../data/facades/train/34.jpg',
 '../../data/facades/train/271.jpg',
 '../../data/facades/train/272.jpg',
 '../../data/facades/train/338.jpg',
 '../../data/facades/train/339.jpg',
 '../../data/facades/train/340.jpg']