HDU 2057 A + B Again

Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

 

Input

The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

 

Output

For each test case,print the sum of A and B in hexadecimal in one line.

 

Sample Input

+A -A +1A 12 1A -9 -1A -12 1A -AA

 

Sample Output

0 2C 11 -2C -90

 

Author

linle

 

Source

校慶杯Warm Up

思路：16進制輸入輸出， 注意“The length of A and B is less than 15. ”  ，也就是說，數據範圍不在int裏面，要用long long。

代碼：

#include<stdio.h>
int main()
{
    int a,b,res;
    while(~scanf("%llX %llX",&a,&b))
    {
        if(a+b>=0)
            printf("%llX\n",a+b);//如果是小寫的x的話，也會wa
        else
            printf("-%llX\n",-a-b);
    }
    return 0;
}