118_leetcode_Palindrome Partitioning

Given a string s, partition s such that every substring of the partition is a palindrome.

Return all possible palindrome partitioning of s.

For example, given s = "aab",
Return

  [
    ["aa","b"],
    ["a","a","b"]
  ]

1:特殊情況；2:遞歸；3:判斷一個字符子串是不是迴文串；4:注意遞歸結束情況

    vector<vector<string> > partition(string s)
    {
        vector<vector<string> > result;
        if(s.empty())
        {
            return result;
        }
        
        vector<string> temp;
        partitionCore(s, 0, temp, result);
        
        return result;
    }
    
    void partitionCore(string s, int index, vector<string> &temp, vector<vector<string> > &result)
    {
        if(s[index] == '\0')
        {
            result.push_back(temp);
            return;
        }
        
        for(int i = index; s[i] != '\0'; i++)
        {
            string tempStr = s.substr(index, i - index + 1);
            if(isPalindromeCore(tempStr.c_str()))
            {
                temp.push_back(tempStr);
                partitionCore(s, i + 1, temp, result);
                temp.pop_back();
            }
        }
    }
    
    bool isPalindromeCore(string s)
    {
        int start = 0;
        int end = (int)s.size() - 1;
        
        while(start < end)
        {
            if(s[start] != s[end])
            {
                return false;
            }
            start++;
            end--;
        }
        
        return true;
    }