【8086彙編(實驗)】 分支結構

題目一：成績評級

寫一個完整的8086彙編語言程序，該程序從鍵盤輸入一個成績，判斷其屬於哪個等級，等級分別爲’A’ (80-100),’B’(60-80),’C’(0-59)，並顯示結果在屏幕上。

源碼：

如果運行報錯或死機，嘗試把中文註釋刪除(分號“；”後面的爲註釋)

;Program:成績評級
;Author:Nonoas
;Date:20191023

.386
.MODEL FLAT

ExitProcess PROTO NEAR32 stdcall, dwExitCode:DWORD

INCLUDE io.h            ; header file for input/output

cr      EQU     0dh     ; carriage return character
Lf      EQU     0ah     ; line feed

.STACK  4096            ; reserve 4096-byte stack

.DATA                   ; reserve storage for data

prompt1 byte "Enter a source:",0
prompt2 byte cr,lf,"The result is:",0
number DWORD ?
str1 byte 40 dup (?)
result DWORD ?


.CODE                           ; start of main program code
_start:

	output prompt1
	input str1,40
	atod str1
	mov number,eax

	cmp eax,59
	jle endc
	cmp eax,80
	jle endb
	cmp eax,100
	jle enda

endc:  
	mov ebx,"C"
	jmp endall
endb:  mov ebx,"B"
	jmp endall
enda:  mov ebx,"A"
	jmp endall

endall:
	mov result,ebx
	output prompt2
	output result


        INVOKE  ExitProcess, 0  ; exit with return code 0
PUBLIC _start                   ; make entry point public

END                             ; end of source code

題目二：1~N的平方

寫出一段完整的80*86程序，實現輸入一個正整數值N後，用兩欄格式顯示從1到N和它們的平方。如：從鍵盤輸入5，則顯示如下內容

數字	平方
1	1
2	4
3	9
4	16
5	25

源碼：

;Program:
;Author:
;Date:

.386
.MODEL FLAT

ExitProcess PROTO NEAR32 stdcall, dwExitCode:DWORD

INCLUDE io.h            ; header file for input/output

cr      EQU     0dh     ; carriage return character
Lf      EQU     0ah     ; line feed

.STACK  4096            ; reserve 4096-byte stack

.DATA                   ; reserve storage for data

prompt byte "Enter a data:",0
sign byte "        num      num^2",cr,lf,0
space byte "    ",0
nextline byte cr,lf,0
number DWORD ?
num1 DWORD ?
num2 DWORD ?
count DWORD 1
num3 byte 10 dup (?)
string byte 40 dup (?)

.CODE                           ; start of main program code
_start:

	output prompt
	input string,40
	atod string
	mov number,eax
	output sign
	cmp eax,count
	jle endall
again:
	mov ecx,count
	mov ebx,count
	imul ebx,count
	dtoa num1,ecx
	output num1
	dtoa num2,ebx
	output num2
	output nextline
	add ecx,1
	mov count,ecx
	cmp ecx,number
	jle again

endall:


        INVOKE  ExitProcess, 0  ; exit with return code 0
PUBLIC _start                   ; make entry point public

END                             ; end of source code