目录:
- 1、搭建maven项目(工具:IDEA 2019.2.3)
- 2、在maven项目中搭建SpringBoot框架
- 3、maven项目中使用jsp(SpringBoot框架)
- 4、自定义SpringBoot配置
- 5、自定义项目启动banner显示(SpringBoot)
- 6、整合MyBatis Plus+MySQL(SpringBoot框架)
- 注:Maven pom.xml详解
1、在pom.xml中导入以下依赖包
<!-- servlet 依赖包 -->
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>javax.servlet-api</artifactId>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>jstl</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-tomcat</artifactId>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
<!-- <scope>provided</scope>-->
</dependency>
2、在webapp文件夹下创建jsp文件(右键webapp -> new jsp/jspx -> 输入jsp文件名)
3、在Controller文件夹下创建测试controller类
@Controller
public class TestJspController {
@RequestMapping(method = {RequestMethod.GET}, value = "/index")
public String info() {
return "index";
}
}
4、创建application.yml文件并配置jsp访问路径
①、创建application:依次点击File -> Project Structure -> 右键main -> new folder,输入文件名resources -> 右键resources选择Resources -> 右键项目中已创建的resources,选择new file,在弹出框中输入application.yml
②、在application.yml中输入
spring:
mvc:
view:
prefix: /
suffix: .jsp
5、启动项目(启动application.java中的main方法)
6、浏览器输入http://localhost:8080/index,测试结果如下