本文是GoLang学习教程中的一道习题,具体题目要求及代码实现如下。
备注:由于天朝GFW屏蔽了GAE,所以GoLang官网及学习教程需要翻墙才能访问。
Exercise: Equivalent Binary Trees
1. Implement the Walk function.
2. Test the Walk function.
Create a new channel ch and kick off the walker:
go Walk(tree.New(1), ch)Then read and print 10 values from the channel. It should be the numbers 1, 2, 3, ..., 10.
3. Implement the Same function using Walk to determine whether t1 and t2 store the same values.
4. Test the Same function.Same(tree.New(1), tree.New(1)) should return true, and Same(tree.New(1), tree.New(2))should return false.
一种实现如下(深度优先中序遍历):
package main
import "code.google.com/p/go-tour/tree"
import "fmt"
// Walk walks the tree t sending all values
// from the tree to the channel ch.
func Walk(t *tree.Tree, ch chan int) {
//fmt.Println("tree=", t)
left := t.Left
right := t.Right
if (left == nil) && (right == nil) {
//fmt.Println("child=", t.Value)
ch <- t.Value
return
}
if left != nil {
Walk(left, ch)
}
if (left != nil) || (right != nil) {
//fmt.Println("parent=", t.Value)
ch <- t.Value
}
if right != nil {
Walk(right, ch)
}
}
// Same determines whether the trees
// t1 and t2 contain the same values.
func Same(t1, t2 *tree.Tree) bool {
ch1 := make(chan int)
ch2 := make(chan int)
go Walk(t1, ch1)
go Walk(t2, ch2)
depth := 10
for i := 0; i < depth; i++ {
x1 := <- ch1
x2 := <- ch2
if x1 != x2 {
return false
}
}
return true
}
func main() {
/*
ch1 := make(chan int)
ch2 := make(chan int)
go Walk(tree.New(1), ch1)
go Walk(tree.New(2), ch2)
for i := 0; i < 10; i++ {
fmt.Println(<-ch1)
}
for i := 0; i < 10; i++ {
fmt.Println(<-ch2)
}
*/
fmt.Println(Same(tree.New(1), tree.New(2)))
}