自定义容器LinkedList,实现部分功能
1.创建Node类,存放节点信息
/**
* 每个节点内三个对象表示
* previous 前一个节点位置
* obj 当前节点数据信息
* next 下一个节点位置
* @author Administrator
*
*/
public class Node {
Node previous;
Object obj;
Node next;
public Node(){
}
public Node(Node previous,Object obj,Node next){
super();
this.previous = previous;
this.obj = obj;
this.next = next;
}
public Object getPrevious() {
return previous;
}
public void setPrevious(Node previous) {
this.previous = previous;
}
public Object getObj() {
return obj;
}
public void setObj(Object obj) {
this.obj = obj;
}
public Object getNext() {
return next;
}
public void setNext(Node next) {
this.next = next;
}
}
2. 实现LinkedList/**
* 编程实现LinkedList
*
* @author Administrator
*
*/
public class MyLinkedList {
private Node first;
private Node last;
private int size;
public MyLinkedList() {
}
public int size() {
return size;
}
// 在链表尾部增加指定对象
public void add(Object obj) {
Node n = new Node();
// 链表头是否为空
if (first == null) {
n.setPrevious(null);
n.setObj(obj);
n.setNext(null);
first = n;
last = n;
} else {
// 向last节点后增加新的节点
n.setPrevious(last);
n.setObj(obj);
n.setNext(null);
last.setNext(n);
last = n;
}
size++;
}
// 向指定索引位置增加对象,新节点的对应关系为:previous指向索引位置节点的前一个节点,next指向索引位置节点
public void add(int index, Object obj) {
rangeCheck(index);
Node temp = node(index);
Node up = temp.previous;
Node newNode = new Node();
newNode.obj = obj;
if (temp != null) {
newNode.previous = up;
up.next = newNode;
newNode.next = temp;
temp.previous = newNode;
size++;
}
}
public void set(int index, Object obj) {
rangeCheck(index);
Node temp = node(index);
if (temp != null) {
temp.obj = obj;
}
}
public Object get(int index) {
rangeCheck(index);
Node temp = node(index);
if (temp != null) {
return temp.obj;
} else {
return null;
}
}
// 移除索引位置节点,1 2 3,将1的下一个设置为3,3的上一个设置为1,实现双向,移除2位置
public void remove(int index) {
Node temp = node(index);
if (temp != null) {
// 索引位置节点的上一个节点
Node up = temp.previous;
// 索引位置节点的下一个节点
Node down = temp.next;
// 上一个节点的next节点位置设置为当前节点的下一个,同理操作下一个节点,实现移除索引位置节点
up.next = down;
down.previous = up;
}
size--;
}
public void clear() {
Node temp = new Node();
if (first != null) {
temp = first;
for (int i = 0; i < size - 1; i++) {
temp.obj = null;
temp = temp.next;
size--;
}
}
}
public void rangeCheck(int index) {
if (index < 0 || index > size - 1) {
try {
throw new Exception();
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
// 寻找节点
public Node node(int index) {
rangeCheck(index);
Node temp = null;
if (first != null) {
//size=50;[0,49],寻找第2个和寻找第48个节点的方法优化分析
//一个简单的优化算法:将index与size/2(szie>>1)进行比较,如果小於则从0开始遍历,如果大於则从49开始向前遍历
if (index<(size>>1)) {
temp = first;
for (int i = 0; i < index; i++) {
temp = temp.next;
}
}else{
temp = last;
for (int i = size-1; i > index; i--) {
temp = temp.previous;
}
}
}
return temp;
}
public static void main(String[] args) {
MyLinkedList list = new MyLinkedList();
list.add("aaa");
list.add(111);
list.add(555);
list.add(1, "ddd");
list.set(1, 444);
System.out.println(list.get(1));
// for (int i = 0; i < list.size(); i++) {
// System.out.println(list.get(i));
// }
}
}