C++期末複習題目彙總
本人彙總了本學期上機考的題目，並借鑑和自己編寫了這些代碼。
///題目如下
1.字母大小寫轉換
#include<iostream>
using namespace std;
void change(char x) {
x += 32;
cout << x << endl;
}
int main() {
char a;
cin >> a;
change(a);
return 0;
}
2.計算圓的周長和麪積
#include<iostream>
using namespace std;
#define PI 3.14
class Circle
{
public:
Circle(double radius) {
this->C = 2 * PI * radius;
this->S = PI * radius * radius;
cout << this->C << " " << this->S << endl;
}
double S;
double C;
};
int main() {
double radius;
cin >> radius;
Circle a(radius);
return 0;
}
3.數據逆序輸出
#include<iostream>
using namespace std;
int function(int n)
{
int temp = 0;
while (n > 0) {
n /= 10;
temp++;
}
return temp;
}
int main() {
int array[10];
int num, x;
cin >> num;
x = function(num);
for (int i = 0; i < x; i++) {
array[i] = num % 10;
num /= 10;
}
for (int i = 0; i < x; i++) {
cout << array[i];
}
return 0;
}
4.判斷是否是閏年
#include<iostream>
using namespace std;
void function(int a )
{
if (a % 4 == 0 && a % 100 != 0 || a % 400 == 0) {
cout << "是" << endl;
}
else {
cout << "不是" << endl;
}
}
int main() {
int year;
cin >> year;
function(year);
return 0;
}
5.打點滴實驗
#include<iostream>
using namespace std;
void calculate(int V)
{
int num = 1, time = 2, sum = 0;
while (V-num > 0) {
V -= num;
num++;
sum += time;
time++;
}
if (V > 0) {
sum += V;
}
cout << sum << endl;
}
int main()
{
int V;
cin >> V;
calculate(V);
return 0;
}
6.母牛生小牛,四年生一頭
#include<iostream>
using namespace std;
int func(int N)
{
if (N < 4)
{
return 1;
}
else
{
return func(N - 1) + func(N - 3);
}
}
int main()
{
int N;
cin >> N;
cout << func(N);
return 0;
}
7.輸出1-100（每行十個），並輸出序號爲素數的元素（一行十個）
代碼一：
#include<iostream>
using namespace std;
int main() {
int arr[100];
for (int i = 0; i < 100; i++)
{
arr[i] = i+1;
}
for (int i = 0; i <100; i+=10)
{
for (int j = 0; j < 9; j++)
{
cout << arr[i + j]<<" ";
}
cout << arr[i + 9] << endl;
}
//尋找100以內素數
int arr1[50];
int temp = 0, count = 0;
for (int i = 2; i <= 100; i++)
{
for (int j = 2; j < i; j++)
{
if (i % j == 0)
{
temp = 1;
break;
}
}
if (temp == 0)
{
count++;
arr1[count-1] = i;
}
temp = 0;
}
cout << arr[arr1[0]] << " ";
for (int i = 1; i<count; i++)
{
if (i % 10 != 9)
{
cout << arr[arr1[i]] << " ";
}
else
{
cout << arr[arr1[i]] << endl;
}
}
return 0;
}
代碼二：
#include<iostream>
using namespace std;
int main()
{
int a[100];
int n = 1;
for (int i = 0; i < 100; i++)
{
a[i] = n;
n++;
}
for (int i = 0; i < 100; )
{
for (int j = 0; j < 9; j++)
{
cout << a[i] << " ";
i++;
}
cout << a[i++] << endl;
}
int m = 1;
cout << 3 << " ";
for (int i = 3; i < 100; i++)
{
int sum = 0;
for (int j = 2; j < i / 2 + 1; j++)
{
int x;
x = i % j;
if (x == 0)
sum++;
}
if (sum == 0)
{
m++;
if (m < 10)
cout << a[i] << " ";
else if (m >= 10)
{
m = 0;
cout << a[i] << endl;
}
}
}
return 0;
}
8.倉庫結算
某倉庫共有ABCDE五種貨物，每天需要補貨的數量不同，每種貨物的單價不同，如下所示。由鍵盤輸入五種貨物需要補貨的數量，請計算出當日倉庫需支付多少貨款。
貨物名稱 貨物單價
A 10
B 5
C 3
D 20
E 13
#include<iostream>
using namespace std;
int main()
{
int m, sum = 0;
char P;
for (int i = 0; i < 5; i++)
{
cin >> P >> m;
switch (P)
{
case'A':
sum += 10 * m;
break;
case'B':
sum += 5 * m;
break;
case'C':
sum += 3 * m;
break;
case'D':
sum += 20 * m;
break;
case'E':
sum += 13 * m;
break;
}
}
cout << sum << endl;
return 0;
}
9.編寫一個評分統計程序。從鍵盤獲取8個評委打分的百分制成績（double類型），統計平均分時，去掉一個最高分和一個最低分其餘6個分數的平均值即爲最後得分。請將這個分數輸出到屏幕上，格式爲：平均成績是XXX。
#include<iostream>
using namespace std;
void func(double arr[])
{
int num = 7, num1;
double sum = 0;
while (num)
{
num1 = num;
num = 0;
for (int i = 0; i < num1; i++)
{
if (arr[i]<arr[i+1])
{
double temp = arr[i];
arr[i] = arr[i + 1];
arr[i + 1] = temp;
num = i;
}
}
}
for (int i = 1; i < 7; i++)
{
sum += arr[i];
}
cout <<"平均成績是"<< sum / 6 << endl;
}
int main()
{
double score[8];
for (int i = 0; i < 8; i++)
{
cin >> score[i];
}
func(score);
return 0;
}
10.編寫一個記錄5個學生的姓名、性別、年齡和學號的程序，要求使用結構數組表示學生信息，用for循環獲得鍵盤輸入的學生記錄的數據，所有數據輸入完畢後，將5個學生的信息在屏幕上輸出，格式要求：按表格行列格式輸出，每行輸出一個學生的信息，按照姓名、性別、年齡、學號的順序，各列信息左對齊，各信息佔10位。
#include<iostream>
#include<iomanip>
#include<string>
using namespace std;
struct Student
{
string name;
string sex;
int age;
string number;
};
Student P[5];
int main()
{
for (int i = 0; i < 5; i++)
{
cin >> P[i].name >> P[i].sex >> P[i].age >> P[i].number;
}
for (int i = 0; i < 5; i++)
{
cout << setiosflags(ios::left)
<< setw(10) << P[i].name
<< setw(10) << P[i].sex
<< setw(10) << P[i].age
<< setw(10) << P[i].number << endl;
}
return 0;
}
11.定義一個結構型變量（包括年、月、日），並從鍵盤上獲取該變量的值，計算該日在本年中是第幾天，輸出到屏幕上，格式爲：“X年X月X日是本年中的第X天。”（提示：注意閏年問題）。
代碼一：
#include<iostream>
using namespace std;
class Date
{
friend void func(Date *p);
public:
Date(int y, int m, int d)
{
this->year = y;
this->month = m;
this->day = d;
}
int year;
int month;
int day;
};
int judgement(int y)
{
if (y % 400 == 0 || y % 4 == 0 && y % 100 != 0) {
return 1;
}
else {
return 0;
}
}
void func(Date &p)
{
int arr[12];
int sum = 0;
if (judgement(p.year))
{
arr[1] = 29;
}
else {
arr[1] = 28;
}
arr[0] = arr[2] = arr[4] = arr[6] = arr[7] = arr[9] = arr[11] = 31;
arr[3] = arr[5] = arr[8] = arr[10] = 30;
for (int i = 0; i < p.month - 1; i++)
{
sum += arr[i];
}
sum += p.day;
cout << p.year << "年" << p.month << "月" << p.day << "日是本年中的第" << sum << "天" << endl;
}
int main()
{
int y, m, d;
cin >> y >> m >> d;
Date a(y, m, d);
func(a);
return 0;
}
代碼二：
#include<iostream>
using namespace std;
struct Date
{
int year;
int month;
int day;
};
bool judge(int y)
{
int sum = 0;
if (y % 100 == 0)
{
if (y % 400 == 0)return true;
else return false;
}
else {
if (y % 4 == 0)return true;
else return false;
}
}
int main()
{
Date d;
cin >> d.year >> d.month >> d.day;
int a[12];
if (judge(d.year))
{
a[1] = 29;
}
else
{
a[1] = 28;
}
a[0] = a[2] = a[4] = a[6] = a[7] = a[9] = a[11] = 31;
a[3] = a[5] = a[8] = a[10] = 30;
int sum = 0;
for (int i = 0; i < d.month - 1; i++)
{
sum += a[i];
}
sum += d.day;
cout << d.year << "年" << d.month << "月" << d.day << "日是本年中的第" << sum << "天" << endl;
return 0;
}
12.從鍵盤輸入一行或幾行字符串，行數由鍵盤輸入，一行字符串用字符數組存儲。請統計所輸入的字符串中26個字母（不區分大小寫）出現的次數，並將出現次數非零的字母統計結果輸出到屏幕上，格式參見樣例。如果沒有字母，請輸出字符串中無字母。
代碼一：
#include<iostream>
using namespace std;
int main()
{
const int N = 80;
char buffer[N];
int k = 0;
const int NUM = 26;
int counts[NUM] = {
0 };
char letters[NUM];
int i = 0;
int count = 0;
int num;
cin >> num;
do {
cin.getline(buffer, N, '\n');
k = 0;
while (buffer[k] != '\0')
{
if (tolower(buffer[k]) >= 'a' && tolower(buffer[k]) <= 'z')
{
i = tolower(buffer[k]) - 'a';
counts[i]++;
}
k++;
}
num--;
} while (num >= 0);
for (i = 0; i < NUM; i++) {
letters[i] = char('a' + i);
if (counts[i] > 0)
{
count++;
cout << letters[i] << ":" << counts[i] << endl;
}
}
if (count == 0) {
cout << "字符串中無字母。" << endl;
}
}
代碼二：
#include<iostream>
using namespace std;
int b[26] = {
0 };
void func(char a)
{
if (a >= 'a' && a <= 'z')
{
b[a - 'a']++;
}
else if (a >= 'A' && a <= 'Z')
{
b[a - 'A']++;
}
}
int main()
{
int n;
cin >> n;
char a[100] = {
0 };
for (int i = 0; i < n + 1; i++)
{
cin.getline(a, 100, '\n');
int j = 0;
while (a[j] != '\0')
{
func(a[j]);
j++;
}
}
int count = 0;//判斷有無字母
for (int i = 0; i < 26; i++)
{
if (b[i] != 0)
{
cout << char(i + 'a') << ":" << b[i] << endl;
count++;
}
}
if (count == 0)
{
cout << "字符串中無字母。" << endl;
}
return 0;
}
13.溫度轉換
#include<iostream>
using namespace std;
int main()
{
double F, C;
cin >> F;
C = (F - 32) / 1.8;
cout << C << endl;
return 0;
}
14.斐波那契數列
遞歸版：
#include<iostream>
using namespace std;
int Fabo(int x)
{
int sum = 0;
if (x == 0)sum = 0;
else if (x == 1)sum = 1;
else sum = sum + Fabo(x - 1) + Fabo(x - 2);
return sum;
}
int main()
{
int x;
cin >> x;
cout << Fabo(x) << endl;
}
非遞歸版：
#include<iostream>
using namespace std;
void func(int n)
{
if (n == 0)
{
cout << 0 << endl;
}
else if (n == 1 || n == 2)
{
cout << 1 << endl;
}
else
{
int a = 1, b = 1, temp = 0;
for (int i = 3; i <= n; i++)
{
temp = a + b;
a = b;
b = temp;
}
cout << temp << endl;
}
}
int main()
{
int n;
cin >> n;
func(n);
return 0;
}
15.有10個小朋友圍成一圈分糖果，老師順次分給每人一定數量糖果（初始值爲偶數）然後按照下列規則調整，所有小朋友同時把自己的糖果分一半給右邊的人，糖果數變爲奇數的人，向老師補要一塊糖果，問經過多少次調整後，大家糖果數一樣多，且每人多少塊。建立兩個函數，一個負責傳遞糖果，一個負責判斷所有人的糖果是否相等。
#include<iostream>
using namespace std;
void func(int arr[],int *arr1) {
for (int i = 1; i < 10; i++)
{
arr1[i] = arr[i] / 2 + arr[i - 1] / 2;
}
arr1[0] = arr[0] / 2 + arr[9] / 2;
for (int i = 0; i < 10; i++)
{
if (arr1[i] % 2 != 0)
{
arr1[i]++;
}
}
for (int i = 0; i < 10; i++)
{
arr[i] = arr1[i];
}
}
int judgement(int arr[])
{
for (int i = 0; i < 10; i++)
{
if (arr[i] != arr[0])
{
return 1;
}
}
return 0;
}
int main()
{
int count = 0;
int arr[10] = {
0 };
int *arr1 =new int[10];
for (int i = 0; i < 10; i++)
{
cin >> arr[i];
}
while (judgement(arr))
{
func(arr,arr1);
count++;
}
cout << count <<" "<<arr[0]<< endl;
system("pause");
return 0;
}
16.歌手大獎賽共有10位評委，爲每位選手打分（double型）。
預賽部分歌手的分數，爲去掉1個最高分、1個最低分後其餘8個分數的平均值；
決賽部分歌手的分數，爲去掉2個最高分、2個最低分後其餘6個分數的平均值。
通過鍵盤輸入10位評委的打分，以及當前處於哪個階段（預賽部分用1表示，決賽部分用2表示）。
主函數中，只負責輸入數據、調用分數計算函數、輸出結果，評分計算部分編寫獨立函數完成。
#include<iostream>
using namespace std;
void func(double* p)
{
for (int i = 0; i < 9; i++)
{
for (int j = 0; j < 9 - i; j++)
{
double temp;
temp = p[j];
p[j] = p[j + 1];
p[j + 1] = temp;
}
}
}
double js(double* p)
{
double sum = 0;
for (int i = 2; i < 8; i++)
{
sum += p[i];
}
return sum / 6.0;
}
double ys(double* p)
{
double sum = 0;
for (int i = 1; i < 9; i++)
{
sum += p[i];
}
return sum / 8.0;
}
int main()
{
double* p = new double[10];
for (int i = 0; i < 10; i++)
{
cin >> p[i];
}
int x;
cin >> x;
if (x == 1) {
cout << ys(p) << endl;
}
if (x == 2) {
cout << js(p) << endl;
}
delete[]p;
return 0;
}
17.編寫一個函數get_average()獲取整型數組元素的平均值。
要求這個函數既可以用來求一維數組元素的平均值，
也可以求二維數組元素的平均值。
在main()函數中通過具體的一維數組Array_1D和二維數組Array_2D測試這個函數。
假定一維數組爲a[5],二維數組爲b[2][3],一維數組和二維數組的變量值由鍵盤分別輸入，
在屏幕上輸出一維數組和二維數組的平均值，平均值間用一個空格分開。
#include<iostream>
using namespace std;
int main()
{
double sum1 = 0, sum2 = 0;
int a[5];
int b[2][3];
for (int i = 0; i < 5; i++)
{
cin >> a[i];
sum1 += a[i];
}
for (int i = 0; i < 2; i++)
{
for (int j = 0; j < 3; j++)
{
cin >> b[i][j];
sum2 += b[i][j];
}
}
cout << sum1 / 5 << " " << sum2 / 6 << endl;
return 0;
}
18.編制程序，調用指針作爲參數的函數，實現下面兩字符串變量的交換。 char* ap=“hello”; char* bp=“how are you”;
交換的結果爲：ap 指向"how are you"，bp 指向"hello"。 (注意：輸出語句中的;和.爲英文符號)
#include<iostream>
using namespace std;
void swap(char* a, char* b)
{
char* t;
t = a;
a = b;
b = t;
}
int main()
{
const char* ap = "hello.";
const char* bp = "how are you;";
swap(ap, bp);
cout << "ap指向" << ap << endl;
cout << "bp指向" << bp << endl;
return 0;
}
19.用字符指針數組，將給定的5個字符串（可以是任意5個國家名字）進行排序並輸出。
#include <iostream>
using namespace std;
int main() {
char* name[5];
char arr[5][100];
for (int i = 0; i < 5; i++)
{
cin >> arr[i];
}
for (int i = 0; i < 5; i++)
{
name[i] = arr[i];
}
for (int i = 0; i < 5; i++)
{
for (int j = 0; j < 4 - i; j++)
{
if (*name[j]>*name[j+1])
{
char* t = name[j];
name[j] = name[j + 1];
name[j + 1] = t;
}
}
}
for (int i = 0; i < 5; i++)
{
cout << name[i] << endl;
}
return 0;
}
20.已知有3名學生及五門課程的成績，要求根據學生的各科平均分排序（降序）,並輸出學生的所有信息和平均分（用指針數組完成）。
#include <iostream>
using namespace std;
struct student {
char name[10];
int score[5];
float aver;
};student a[3];
int main() {
for (int i = 0; i < 3; i++)
{
cin >> a[i].name;
float num = 0;
for (int j = 0; j < 5; j++)
{
cin >> a[i].score[j];
num += (float)a[i].score[j];
}
a[i].aver = num / 5;
}
student* p[3];
for (int i = 0; i < 3; i++)
{
p[i] = &a[i];
}
for (int i = 0; i < 2; i++)
{
for (int j = 0; j < 2 - i; j++)
{
if (p[j]->aver < p[j + 1]->aver) {
student* temp;
temp = p[j];
p[j] = p[j + 1];
p[j + 1] = temp;
}
}
}
for (int i = 0; i < 3; i++)
{
cout << p[i]->name << " ";
for (int j = 0; j < 5; j++)
{
cout << p[i]->score[j] << " ";
}
cout << p[i]->aver << endl;
}
return 0;
}
21.請編寫函數實現將一個數值插入到數組中適當的位置，使新數組按降序排列，並將插入的位置輸出到屏幕上。 說明：1）原數組大小和數值由鍵盤輸入，動態創建數組； 2）插入的數值由鍵盤輸入。
3)如果插入數據與原數組中某數據相同，則插在該數據之前。
#include<iostream>
using namespace std;
int main()
{
int num,num1;
cin >> num;
int* p = new int[100];
int* x = new int[100];
for (int i = 0; i < num; i++)
{
cin >> p[i];
}
for (int i = 0; i < num - 1; i++)
{
for (int j = 0; j < num - i - 1; j++)
{
if (p[j] < p[j + 1])
{
int temp = p[j];
p[j] = p[j + 1];
p[j + 1] = temp;
}
}
}
cin >> num1;
x[0] = num1;
for (int i = 0; i < num; i++)
{
x[i + 1] = p[i];
}
int count = 1;
for (int i = 0; i < num ; i++)
{
if (x[i] < x[i + 1])
{
int temp = x[i];
x[i] = x[i + 1];
x[i + 1] = temp;
count++;
}
}
cout << count << endl;
system("pause");
return 0;
}
22.老王的密碼
#include<iostream>
using namespace std;
int main()
{
int num = 0;
char* p = new char[100];
cin >> p;
for (int i = 0; i < 100; i++)
{
if (p[i] == NULL) {
num = i;
break;
}
}
for (int i = 0; i < num; i++) {
if (p[i] >= 'a' && p[i] <= 'z')
{
if (p[i] >= 'a' && p[i] <= 'c')
{
p[i] = '2';
}
else if(p[i] >= 'd' && p[i] <= 'f')
{
p[i] = '3';
}
else if (p[i] >= 'g' && p[i] <= 'i')
{
p[i] = '4';
}
else if (p[i] >= 'j' && p[i] <= 'l')
{
p[i] = '5';
}
else if (p[i] >= 'm' && p[i] <= 'o')
{
p[i] = '6';
}
else if (p[i] >= 'p' && p[i] <= 's')
{
p[i] = '7';
}
else if (p[i] >= 't' && p[i] <= 'v')
{
p[i] = '8';
}
else
{
p[i] = '9';
}
}
else if (p[i] >= 'A' && p[i] <= 'Z') {
p[i] = p[i] + 33;
}
else
{
p[i] = p[i];
}
}
for (int i = 0; i < num; i++) {
cout << p[i];
}
system("pause");
return 0;
}
23.矩形類
#include<iostream>
using namespace std;
class Rec {
public:
Rec(double R_len,double R_wid) {
this->R_len = R_len;
this->R_wid = R_wid;
this->S = this->R_len * this->R_wid;
}
double R_len;
double R_wid;
double S;
Rec compare(Rec rec1, Rec rec2);
};
Rec Rec::compare(Rec rec1, Rec rec2) {
if (rec1.S > rec2.S) {
return rec1;
}
else {
return rec2;
}
}
int main() {
double l, w;
cin >> l >> w;
Rec rec1(5.2,4.3);
Rec rec2(100,20);
Rec rec3(l, w);
cout <<(rec1.compare(rec1.compare(rec1,rec2),rec3)).S << endl;
system("pause");
return 0;
}
24.三角類
#include<iostream>
using namespace std;
class Tri {
public:
Tri(int a, int b, int c) {
this->L1 = a;
this->L2 = b;
this->L3 = c;
}
int L1;
int L2;
int L3;
void judgement(int a1, int a2, int a3);
};
void Tri::judgement(int a1,int a2,int a3) {
if ((a1 + a2 > a3) && (a1 + a3 > a2) && (a2 + a3 > a1)) {
if (a1 == a2 && a2== a3) {
cout << "A equileteral triangle" << endl;
}
else if ((a1 == a2) | (a1 == a3) | (a2 == a3) ) {
cout << "A isosceles triangle" << endl;
}
else if ((a1 * a1 == a2 * a2 + a3 * a3) || (a2 * a2 == a1 * a1 + a3 * a3) || (a3 * a3 == a2 * a2 + a1 * a1)) {
cout << "A right triangle" << endl;
}
else {
cout << "A triangle" << endl;
}
}
else {
cout << "Not a triangle" << endl;
}
}
int main() {
int a, b, c;
cin >> a >> b >> c;
Tri S(a, b, c);
S.judgement(S.L1, S.L2, S.L3);
system("pause");
return 0;
}
25.時間類
#include<iostream>
using namespace std;
class Time {
public:
Time(int a, int b, int c);
void func(bool d);
int Year;
int Month;
int Day;
};
Time::Time(int a, int b, int c) {
this->Year = a;
this->Month = b;
this->Day = c;
}
void Time::func(bool d) {
if (d == true) {
cout << Year << "-" << Month << "-" << Day << endl;
}
else {
cout << Year << "年" << Month << "月" << Day << "日" << endl;
}
}
int main() {
char str[15];
int a, b, c, i;
bool e;
cin >> a >> b >> c>> str;
for (i = 0; str[i]; i++)
{
if (str[i] == '.')
break;
}
if (str[i])
e = false;
else
e = true;
Time T(a, b, c);
T.func(e);
system("pause");
return 0;
}
26.員工薪金管理類
#include<iostream>
#include<string>
using namespace std;
class employee
{
public:
int num;
string name;
int money;
int year;
int month;
int day;
employee(int a, std::string b, int c, int d, int e, int f)
{
this->num = a;
this->name = b;
this->money = c;
this->year = d;
this->month = e;
this->day = f;
}
int sum(int x, int y);
};
int employee::sum(int x, int y)
{
int time = (x - year) * 12 + y - month;
int sum = time * money;
return sum;
}
int main()
{
employee a(1, "wang", 5000, 2000, 10, 23);
employee b(2, "liu", 4500, 2008, 1, 20);
employee c(3, "huo", 3800, 2003, 7, 3);
employee d(4, "ma", 5300, 2015, 4, 10);
employee e(5, "meng", 6000, 2016, 3, 16);
int x, y, z;
cin >> x >> y >> z;
switch (x) {
case 1:
cout << a.name << " " << a.sum(y, z) << endl;
break;
case 2:
cout << b.name << " " << b.sum(y, z) << endl;
break;
case 3:
cout << c.name << " " << c.sum(y, z) << endl;
break;
case 4:
cout << d.name << " " << d.sum(y, z) << endl;
break;
case 5:
cout << e.name << " " << e.sum(y, z) << endl;
break;
}
return 0;
}
以上就是一些題目，不敢保證代碼寫的很完美，僅供參考。