2021-05-31柯里化實現累加函數

題源

百度技術一面

題目

柯里化實現累加函數

解答

function createCurry(func, args) {
  var arity = func.length;
  var args = args || [];
  var fn = function () {
    var args_fn = [].slice.call(arguments);
    args = args.concat(args_fn);
    if (args.length < arity) {
      return createCurry.call(this, func, args);
    }
    return func.apply(this, args);
  }
  return fn;
}

function sum(a, b, c) {
  return a + b + c;
}

var newsum = createCurry(sum)
console.log(newsum(11)(14)(12));