檢查傳遞給 Bash 腳本的參數數量 - Check number of arguments passed to a Bash script

問題：

I would like my Bash script to print an error message if the required argument count is not met.如果未滿足所需的參數計數，我希望我的 Bash 腳本打印錯誤消息。

I tried the following code:我嘗試了以下代碼：

#!/bin/bash
echo Script name: $0
echo $# arguments 
if [$# -ne 1]; 
    then echo "illegal number of parameters"
fi

For some unknown reason I've got the following error:由於某些未知原因，我收到以下錯誤：

test: line 4: [2: command not found

What am I doing wrong?我究竟做錯了什麼？

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解決方案：

參考一： https://en.stackoom.com/question/1FuZG
參考二： https://stackoom.com/question/1FuZG