检查传递给 Bash 脚本的参数数量 - Check number of arguments passed to a Bash script

问题：

I would like my Bash script to print an error message if the required argument count is not met.如果未满足所需的参数计数，我希望我的 Bash 脚本打印错误消息。

I tried the following code:我尝试了以下代码：

#!/bin/bash
echo Script name: $0
echo $# arguments 
if [$# -ne 1]; 
    then echo "illegal number of parameters"
fi

For some unknown reason I've got the following error:由于某些未知原因，我收到以下错误：

test: line 4: [2: command not found

What am I doing wrong?我究竟做错了什么？

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解决方案：

参考一： https://en.stackoom.com/question/1FuZG
参考二： https://stackoom.com/question/1FuZG