如何计算列表中的唯一值 - How do I count unique values inside a list

问题：

So I'm trying to make this program that will ask the user for input and store the values in an array / list.所以我正在尝试制作这个程序，它会要求用户输入并将值存储在数组/列表中。
Then when a blank line is entered it will tell the user how many of those values are unique.然后当输入一个空行时，它会告诉用户这些值中有多少是唯一的。
I'm building this for real life reasons and not as a problem set.我是出于现实生活的原因而不是作为一个问题来构建它。

enter: happy
enter: rofl
enter: happy
enter: mpg8
enter: Cpp
enter: Cpp
enter:
There are 4 unique words!

My code is as follows:我的代码如下：

# ask for input
ipta = raw_input("Word: ")

# create list 
uniquewords = [] 
counter = 0
uniquewords.append(ipta)

a = 0   # loop thingy
# while loop to ask for input and append in list
while ipta: 
  ipta = raw_input("Word: ")
  new_words.append(input1)
  counter = counter + 1

for p in uniquewords:

..and that's about all I've gotten so far. ..这就是我到目前为止所获得的全部内容。
I'm not sure how to count the unique number of words in a list?我不确定如何计算列表中唯一的单词数？
If someone can post the solution so I can learn from it, or at least show me how it would be great, thanks!如果有人可以发布解决方案，以便我可以从中学习，或者至少告诉我它会很棒，谢谢！

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解决方案：

参考一： https://en.stackoom.com/question/pXAW
参考二： https://stackoom.com/question/pXAW