C++ 函数模板偏特化？ - C++ function template partial specialization?

问题：

I know that the below code is a partial specialization of a class:我知道下面的代码是一个类的部分特化：

template <typename T1, typename T2> 
class MyClass { 
  … 
}; 


// partial specialization: both template parameters have same type 
template <typename T> 
class MyClass<T,T> { 
  … 
}; 

Also I know that C++ does not allow function template partial specialization (only full is allowed).我也知道 C++ 不允许函数模板部分特化（只允许完整）。 But does my code mean that I have partially specialized my function template for one/same type arguments?但是我的代码是否意味着我已经部分地为一个/相同类型的参数专门化了我的函数模板？ Because it works for Microsoft Visual Studio 2010 Express!因为它适用于 Microsoft Visual Studio 2010 Express！ If no, then could you please explain the partial specialization concept?如果不是，那么您能否解释一下部分专业化的概念？

#include <iostream>
using std::cin;
using std::cout;
using std::endl;

template <typename T1, typename T2> 
inline T1 max (T1 const& a, T2 const& b) 
{ 
    return a < b ? b : a; 
} 

template <typename T> 
inline T const& max (T const& a, T const& b)
{
    return 10;
}


int main ()
{
    cout << max(4,4.2) << endl;
    cout << max(5,5) << endl;
    int z;
    cin>>z;
}

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解决方案：

参考： https://stackoom.com/en/question/Xp9U