問題：
How does the following JavaScript work?以下 JavaScript 是如何工作的？
I understand that it is minified code.我知道它是縮小的代碼。 I have tried de-obfuscating it a little, but I can't get a clear concept of how it achieves this effect.我曾嘗試對其進行一些去混淆處理，但我無法清楚地瞭解它是如何實現這種效果的。 I can see that it is using Strings for iteration of some kind, use of the Date object, strange string manipulation, Math functions, then the code prints itself.我可以看到它使用字符串進行某種迭代，使用日期對象，奇怪的字符串操作，數學函數，然後代碼打印自己。
How could the same effect be rewritten with a minimal example?如何用最小的例子重寫相同的效果？
eval(z='p="<"+"pre>"/* ,.oq#+ ,._, */;for(y in n="zw24l6k\
4e3t4jnt4qj24xh2 x/* =<,m#F^ A W###q. */42kty24wrt413n243n\
9h243pdxt41csb yz/* #K q##H######Am */43iyb6k43pk7243nm\
r24".split(4)){/* dP cpq#q##########b, */for(a in t=pars\
eInt(n[y],36)+/* p##@###YG=[#######y */(e=x=r=[]))for\
(r=!r,i=0;t[a/* d#qg `*PWo##q#######D */]>i;i+=.05)wi\
th(Math)x-= /* aem1k.com Q###KWR#### W[ */.05,0>cos(o=\
new Date/1e3/* .Q#########Md#.###OP A@ , */+x/PI)&&(e[~\
~(32*sin(o)*/* , (W#####Xx######.P^ T % */sin(.5+y/7))\
+60] =-~ r);/* #y `^TqW####P###BP */for(x=0;122>\
x;)p+=" *#"/* b. OQ####x#K */[e[x++]+e[x++\
]]||(S=("eval"/* l `X#####D , */+"(z=\'"+z.spl\
it(B = "\\\\")./* G####B" # */join(B+B).split\
(Q="\'").join(B+Q/* VQBP` */)+Q+")//m1k")[x/2\
+61*y-1]).fontcolor/* TP */(/\\w/.test(S)&&"#\
03B");document.body.innerHTML=p+=B+"\\n"}setTimeout(z)')//