前臺js
window.atob();
window.btoa();
後臺
import java.io.UnsupportedEncodingException;
import java.net.URLDecoder;
import java.net.URLEncoder;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import org.apache.log4j.Logger;
/**
-
@author zxy
-
@date 2020年8月24日 上午11:20:16
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@Description : 字符串加密類
*/
public class BtoAAtoB {private static Logger log = Logger.getLogger(“BtoAAtoB.class”);
private static String base64hash = “ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/”;
public static boolean isMatcher(String inStr, String reg) {
Pattern pattern = Pattern.compile(reg);
Matcher matcher = pattern.matcher(inStr);
if (matcher.matches()) {
return true;
}
return false;
}/**
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btoa method
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@param inStr
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@return
*/
public static String btoa(String inStr) {if (inStr == null || isMatcher(inStr, “([^\u0000-\u00ff])”)) {
return null;
}StringBuilder result = new StringBuilder();
int i = 0;
int mod = 0;
int ascii;
int prev = 0;
while (i < inStr.length()) {
ascii = inStr.charAt(i);
mod = i % 3;
switch (mod) {
case 0:
result.append(String.valueOf(base64hash.charAt(ascii >> 2)));
break;
case 1:
result.append(String.valueOf(base64hash.charAt((prev & 3) << 4 | (ascii >> 4))));
break;
case 2:
result.append(String.valueOf(base64hash.charAt((prev & 0x0f) << 2 | (ascii >> 6))));
result.append(String.valueOf(base64hash.charAt(ascii & 0x3f)));
break;
}
prev = ascii;
i++;
}
if (mod == 0) {
result.append(String.valueOf(base64hash.charAt((prev & 3) << 4)));
result.append("==");
} else if (mod == 1) {
result.append(String.valueOf(base64hash.charAt((prev & 0x0f) << 2)));
result.append("=");
}
return result.toString();
}
-
/**
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atob method 逆轉encode的思路即可
-
@param inStr
-
@return
*/
public static String atob(String inStr) {
if (inStr == null)
return null;
inStr = inStr.replaceAll("\s|=", “”);
StringBuilder result = new StringBuilder();
int cur;
int prev = -1;
int mod;
int i = 0;
while (i < inStr.length()) {
cur = base64hash.indexOf(inStr.charAt(i));
mod = i % 4;
switch (mod) {
case 0:
break;
case 1:
result.append(String.valueOf((char) (prev << 2 | cur >> 4)));
break;
case 2:result.append(String.valueOf((char) ((prev & 0x0f) << 4 | cur >> 2)));break;case 3:result.append(String.valueOf((char) ((prev & 3) << 6 | cur)));break;}prev = cur;i++;
}
return result.toString();
}