Learn python the hard way Ex48更復雜的用戶輸入

經過半天的綢繆，敲擊，檢錯，修正，終於完成了第48小節作者留的作業，雖然代碼看起來很糟糕，但是收穫不小，我是菜鳥，大神勿噴啊，嘎嘎嘎

#encoding:utf-8
import re


def scan(sentence = None):

    directions = ['north','south','east','west']
    verbs      = ['go','kill','eat']
    stops      = ['the','in','of']
    nouns      = ['bear','princess']
    reward     = []
    global  EN

    if sentence == None:         # 如果是***不傳參***，就請求輸入
        command = raw_input("Please input your command > ")
        while command == '':    # 如果輸入***爲空***，就再次請求
            command = raw_input("Please input your command > ")
    else:                       # 如果是***傳參***，就用參數作爲輸入
        command = sentence

    words = command.split()     # 將句子分離爲單詞序列
    r1 = r"^[0-9]+$"            # 純數字的正則表達式

    for word in words:
        if re.match(r1,word) != None:# 判斷是否能夠匹配
            word = int(word)
        if type(word) == str :    # 判斷單詞是否爲***字符串***類型
            for direction in directions:    # 判斷單詞是否在***方向***列表內
                if direction == word:
                    reward.append(('direction', word))
                    EN = True
                    break
                else:
                    EN = False
            if EN == True:
                continue

            for verb in verbs:              # 判斷單詞是否在***動詞***列表內
                if verb == word:
                    reward.append(('verb', word))
                    EN = True
                    break
                else:
                    EN = False
            if EN == True:
                continue

            for stop in stops:              # 判斷單詞是否在***頓詞***列表內
                if stop == word:
                    reward.append(('stop', word))
                    EN = True
                    break
                else:
                    EN = False
            if EN == True:
                continue

            for noun in nouns:              # 判斷單詞是否在***名詞***列表內
                if noun == word:
                    reward.append(('noun', word))
                    EN = True
                    break
                else:
                    EN = False
            if EN == False:
                reward.append(('error', word))
            
        elif (type(word) == int )or(type(word) == float)\
                or(type(word) == long )or(type(word) == complex):
            reward.append(('number', word))

        else:
            reward.append(('error', word))
            break
    return reward

用nose工具測試結果如下：