Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container and n is at least 2.
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用雙指針,代表數組的第一個和最後一個,進行計算判斷當前容器的最大值。如果左邊比右邊高度低,左邊的指針往右移動,反之,右邊的指針往左移動。
public int maxArea(int[] height) {
if(height.length<2) return 0;
int ans = 0;
int left =0,right = height.length-1;
while(left<right){
int value = (right-left)*Math.min(height[left], height[right]);
if(value > ans) ans = value;
if(height[left]<height[right]){
left++;
}else{
right--;
}
}
return ans;
}