[編程題]字符串分隔

題目描述

•連續輸入字符串，請按長度爲8拆分每個字符串後輸出到新的字符串數組；
•長度不是8整數倍的字符串請在後面補數字0，空字符串不處理。

輸入描述:
連續輸入字符串(輸入2次,每個字符串長度小於100)

輸出描述:
輸出到長度爲8的新字符串數組

輸入例子:
abc
123456789

輸出例子:
abc00000
12345678
90000000

思路解答：

#include<iostream>
#include<vector>
#include<string>
using namespace std;
int main()
{
vector<string> strarr;
string str;

while(getline(cin,str))
{
    int len =str.size();
    int num=len%8;
    if(num!=0)
    {
        str.insert(str.end(),8-num,'0');
    }
    int count=str.size()/8;
    for(int i=0;i<count;i++)
    {
        string str_tmp=str.substr(8*i,8);
        strarr.push_back(str_tmp);
    }
}
for(int i=0;i<strarr.size();i++)
{
    cout<<strarr[i]<<endl;
}
    return 0;
}

注意：
1.substr的用法

string substr (size_t pos = 0, size_t len = npos) const;//從指定位置返回指定長度的子字符串

例題

// string::substr
#include <iostream>
#include <string>

int main ()
{
  std::string str="We think in generalities, but we live in details.";
                                           // (quoting Alfred N. Whitehead)

  std::string str2 = str.substr (3,5);     // "think"

  std::size_t pos = str.find("live");      // position of "live" in str

  std::string str3 = str.substr (pos);     // get from "live" to the end

  std::cout << str2 << ' ' << str3 << '\n';

  return 0;
}

2.insert的用法

string (1)  
 string& insert (size_t pos, const string& str);
substring (2)   
 string& insert (size_t pos, const string& str, size_t subpos, size_t sublen);
c-string (3)    
 string& insert (size_t pos, const char* s);
buffer (4)  
 string& insert (size_t pos, const char* s, size_t n);
fill (5)    
 string& insert (size_t pos, size_t n, char c);
    void insert (iterator p, size_t n, char c);
single character (6)    
iterator insert (iterator p, char c);
range (7)   
template <class InputIterator>
   void insert (iterator p, InputIterator first, InputIterator last);

3.錯誤的地方

int count=str.size()/8;一開始寫的是int count=len/8;