一直在默默地學習python, 但是隻是作為初級學習者,從來沒有真正應用過。今天工作中剛好有批量file replace content的job, 為了方便自己,提供工作效率,所以也就為自己量身定做了一個tool,順便也體會一下python 在文件處理方面的強大。
當前文件夾下的批量文件的content replace實現
代碼如下:
#coding=utf-8
# replace string to the other string
# e: replace '../../resource/' to'../resource/resource/'
import re
import glob
import os
cwd = os.getcwd()
FILEPATH = cwd + '\\'+'*.htm'
NEWPATH = cwd + r'\new'
flist = glob.glob(FILEPATH)
for fpath in flist:
fobj = file(str(fpath))
strContent = fobj.read()
strContent = strContent.replace('../../resource/','../resource/resource/')
strContent = strContent.replace('../css/','../resource/css/')
strContent = strContent.replace('../../images/','../resource/images/')
fobj.close()
if os.path.exists(NEWPATH):
print
else:
os.mkdir(NEWPATH)
newfile = open(NEWPATH +'\\'+ os.path.basename(fpath),'w')
newfile.write(strContent)
newfile.close()
print NEWPATH +'\\'+ os.path.basename(fpath) +'replace successed'