# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def sortedArrayToBST(self, nums):
"""
:type nums: List[int]
:rtype: TreeNode
"""
l = len(nums)
if not nums:
return None
root = TreeNode(nums[l//2])
root.left = self.sortedArrayToBST(nums[:l//2])
root.right = self.sortedArrayToBST(nums[l//2+1:])
return root
108. 将有序数组转换为二叉搜索树
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