SqlServer Function 實例

① sql server function 創建

這裏使用一個計算年齡精確到分的function作爲一個demo,

create Function [dbo].[fn_GetAge]
(
  @BIRTHDAY DateTime ,
  @MATH_DATEE DateTime
) returns Varchar(20)

Begin
DECLARE 
  @n_minute   decimal(10,0),
  @n_Hour     decimal(10,0) ,
  @n_Days     decimal(10,0) ,
  @n_Months   decimal(10,0) ,
  @n_Years    decimal(10,0),
  
  @v_Return Varchar(20)
  
  set @n_Years =datediff(YEAR,@BIRTHDAY,@MATH_DATEE) ;
  set @n_Months = datediff(MONTH,@BIRTHDAY,@MATH_DATEE) ;
  set @n_Days =datediff(DAY,@BIRTHDAY,@MATH_DATEE) ;
  set @n_Hour =datediff(HOUR,@BIRTHDAY,@MATH_DATEE) ;
  set @n_minute = datediff(MINUTE,@BIRTHDAY,@MATH_DATEE) ;
  set @v_Return='0';
  
  IF @n_Years = 0
    BEGIN
        IF @n_Months = 0
          BEGIN
            IF @n_Days = 0
                BEGIN
                    IF @n_Hour = 0
                        BEGIN
                            set @v_Return = convert(varchar(2),@n_minute) + '分';
                        END
                    ELSE
                        BEGIN
                            set @v_Return = convert(varchar(2),@n_Hour) + '小時';
                        END
                END
            ELSE
                BEGIN
                    set @v_Return = convert(varchar(2),@n_Days) + '天';
                END
          END
        ELSE
            BEGIN
                set @v_Return = convert(varchar(2),@n_Months) + '月';
            END
    END 
  ELSE 
      BEGIN
        set @v_Return = convert(varchar(2),@n_Years) + '歲';
      END
  

  Return @v_Return; 
End;


GO

② sql server function 使用

select dbo.fn_GetAge('2012-04-25 03:00:00.000','2012-04-25 06:42:00.000') as 年齡

結果：