You need to find the largest value in each row of a binary tree.
Example:
Input: 1 / \ 3 2 / \ \ 5 3 9 Output: [1, 3, 9]
題解如下:
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List<Integer> largestValues(TreeNode root) {
List<Integer> res = new ArrayList<>();
Queue<TreeNode> queue = new LinkedList<>();
if(root == null)
return res;
res.add(root.val);
if(root.left != null)
queue.add(root.left);
if(root.right != null)
queue.add(root.right);
while(!queue.isEmpty()) {
int size = queue.size();
int max = Integer.MIN_VALUE;
for(int i = 0;i < size;i++) {
TreeNode node = queue.poll();
if(node.left != null) queue.add(node.left);
if(node.right != null) queue.add(node.right);
max = Math.max(max,node.val);
}
res.add(max);
}
return res;
}
}