将多个脚本组成的文件拆开

文件里是多个连贯的脚本,需要将它们拆开
1.将文件内容存入一个变量不是好办法,有待改进
#!/usr/bin/perl -w
$tmp1 = `cat 111`;
$count = 1;
                while () {
                if ( $tmp1 =~ /(#!.*?)(#!.*)/s) {
                                $tmp2 = $1;
                                $tmp1 = $2;
                                open RESULT, "> result$count";
                                print RESULT "$tmp2";
                                close     RESULT;
                                }
                else        {
                                open RESULT,"> result$count";
                                print RESULT "$tmp1";
                                close RESULT;
                                exit 0;
                                }
                $count += 1;
                }
2.逐行匹配
#!/usr/bin/perl -w
while (<>) {
                if (/^#!.*/) {
                                $count += 1;
                                open RESULT, ">> result$count";
                                print RESULT "$_";
                                }
                else {
                                print RESULT "$_";
                                }
                }

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