首先感謝，資料由網上的查詢共享並保存下來的，該資料完全是用來學習，希望大家有用。
1.在列表中存在一個名爲copy的方法，就像字面意思一樣copy方法是用於複製列表元素的，示例如下：
1 names = [‘Zhangsan’,’Lisi’,’WangErgou’]2 names2 = names.copy()3 print(names,names2)
當然執行結果也跟想象中是一樣的：
[‘Zhangsan’,’Lisi’,’WangErgou’] [‘Zhangsan’,’Lisi’,’WangErgou’]
如果修改了其中一項元素，會不會影響複製體呢？
1 names = [‘Zhangsan’,’Lisi’,’WangErgou’]2 names2 = names.copy()3 print(names,names2)4 names[1] = “Zhaowu”5 print(names,names2)
結果顯而易見，複製體和本體互不影響，結果如下：
1 [‘Zhangsan’,’Lisi’,’WangErgou’] [‘Zhangsan’,’Lisi’,’WangErgou’]2 [‘Zhangsan’,’Zhaowu’,’WangErgou’] [‘Zhangsan’,’Lisi’,’WangErgou’]
那麼列表嵌套是否也適用呢，測試一下：
1 names = [‘Liuneng’,’Zhaosi’,[’SongXiaofeng’,’LiuDanaodai'],’XieGuangkun’]2 names2 = names.copy()3 print(names,names2)4 names[2][0] = ‘XieDajiao’5 print(names,names2)
額，結果好像有點不同：
1 [‘Liuneng’,’Zhaosi’,[’SongXiaofeng’,’LiuDanaodai'],'XieGuangkun'] [‘Liuneng’,’Zhaosi’,[’SongXiaofeng’,’LiuDanaodai'],’XieGuangkun’]2 [‘Liuneng’,’Zhaosi’,[’XieDajiao’,’LiuDanaodai'],’XieGuangkun’] [‘Liuneng’,’Zhaosi’,[’XieDajiao’,’LiuDanaodai'],’XieGuangkun’]
原來主列表只是存儲了嵌套列表在內存中的地址，而不是所看到的數據，copy的也只是嵌套列表的地址，但兩個地址指向的是內存中同一塊區域，所以在對嵌套列表進行修改時，只是通過了兩個複製地址而修改了真實數據，所以兩個列表的元素都被改掉了。
當然，肯定會有完全獨立的複製的需求，此時則需要導入一個copy模塊來實現了：
copy 2 names = ['zhao','qian',['sun','li'],'zhou'] 3 names2 = copy.copy(names) 4 print(names,names2) 5 names[2][0] = 'wu' 6 print(names,names2)
執行之後得到結果：
1 ['zhao','qian',['sun','li'],'zhou’] ['zhao','qian',['sun','li'],'zhou’]2 ['zhao','qian',[‘wu','li'],'zhou’] ['zhao','qian',['wu','li'],'zhou']
-.-# 好吧，copy模塊的copy方法和python列表的內置函數copy是一樣的，想要完全複製則需要深層copy：
1 import copy2 names = ['zhao','qian',['sun','li'],'zhou']3 names2 = copy.deepcopy(names)4 print(names,names2)5 names[2][0] = 'wu'6 print(names,names2)
執行之後得到結果：
1 ['zhao','qian',['sun','li'],'zhou’] ['zhao','qian',['sun','li'],'zhou’]2 ['zhao','qian',[‘sun','li'],'zhou’] ['zhao','qian',['wu','li'],'zhou']
好了，最後終於得到的完全複製的結果。