将内容转换为EasyUI树的数据格式

        public StringBuilder GetChildJsonStr(V_Zd_SStation station)
        {
            StringBuilder str = new StringBuilder();
            str.Append("{\"id\":\"" + station.SStation + "\",\"text\":\"" + station.SStationName + "\"");
            if (station.childNode != null)
            {
                str.Append(",\"children\":[");
                foreach (var item in station.childNode)
                {
                    //Recursive traversal of sub-nodes
                    str.Append(GetChildJsonStr(item));
                }
                str = new StringBuilder(str.ToString().TrimEnd(','));
                str.Append("]");
            }
            str.Append("},");
            return str;
        }

其中，v_zd_sstation为一个根节点对象。根节点下面会有子节点，从而形成树形结构。

 

构建树的方法：

 private List<V_Zd_SStation> _StnList = null;        
private void BuildingTree(ref V_Zd_SStation rootNode)
        {
            //remove the node
            _StnList.Remove(rootNode);
            string parentStation = rootNode.SStation;
            rootNode.childNode = new List<V_Zd_SStation>();
            rootNode.childNode = _StnList.FindAll(item => item.ParentSStation == parentStation);
            int childCount = rootNode.childNode.Count;
            //Traversing through all child nodes
            for (int i = 0; i < childCount; i++)
            {
                V_Zd_SStation item = rootNode.childNode[i];
                BuildingTree(ref item);
            }
        }

算是日常总结吧，我写的可能也不是很好，如果各位有更好的方法，麻烦评论区告知下，谢谢~~~