給定一組無重複數據,輸出數據全排列。
有兩種解法,一種是自己設計算法實現全排列,另一種是調用庫函數。
詳解思路這位博主的文章解釋得較爲詳細。
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
void dealFunc(vector<int> nums, vector< vector<int>> &vv, int left, int right)
{
if ( left >= right) {
vv.push_back(nums);
return;
}
for ( int i = left; i <= right; i++ ) {
swap( nums[left], nums[i]);
dealFunc( nums, vv, left+1, right);
swap( nums[left], nums[i]);
}
}
int main(void)
{
vector< vector<int>> vv;
vector<int> nums;
int val;
while ( cin >> val ) {
nums.push_back(val);
}
dealFunc( nums, vv, 0, nums.size()-1);
for ( size_t i = 0; i < vv.size(); i++ ) {
vector<int> &v = vv[i];
for ( auto a : v )
cout << ' ' << a;
cout << endl;
}
return 0;
}
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int main(void)
{
vector< vector<int>> vv;
vector<int> nums;
int val;
while ( cin >> val ) {
nums.push_back(val);
}
vector<int> v1(nums);
vector<int> v2(nums);
vv.push_back(nums);
while ( prev_permutation( v1.begin(), v1.end()) )
vv.push_back(v1);
while ( next_permutation( v2.begin(), v2.end()) )
vv.push_back(v2);
for ( size_t i = 0; i < vv.size(); i++ ) {
vector<int> &v = vv[i];
for ( auto a : v )
cout << ' ' << a;
cout << endl;
}
return 0;
}